如何在PHPUnit中捕获PHP警告 [英] How to catch PHP Warning in PHPUnit

问题描述

我正在编写测试用例，这是我的一个问题.

I am writing test cases and here is a question I have.

所以说我正在测试一个简单的功能someClass::loadValue($value)

So say I am testing a simple function someClass::loadValue($value)

正常的测试用例很容易，但是假设传入null或-1时，函数调用会生成PHP警告，这被认为是错误.

The normal test case is easy, but assume when passing in null or -1 the function call generates a PHP Warning, which is considered a bug.

问题是，如何编写我的PHPUnit测试用例，以便在函数正常处理null/-1时成功，而在抛出PHP警告时失败?

The question is, how do I write my PHPUnit test case so that it succeeds when the functions handles null/-1 gracefully, and fail when there is a PHP Warning thrown?

谢谢

推荐答案

PHPUnit_Util_ErrorHandler::handleError()根据错误代码抛出几种异常类型之一:

PHPUnit_Util_ErrorHandler::handleError() throws one of several exception types based on the error code:

• PHPUnit_Framework_Error_Notice用于E_NOTICE，E_USER_NOTICE和E_STRICT
• PHPUnit_Framework_Error_Warning用于E_WARNING和E_USER_WARNING
• PHPUnit_Framework_Error其他所有

• PHPUnit_Framework_Error_Notice for E_NOTICE, E_USER_NOTICE, and E_STRICT
• PHPUnit_Framework_Error_Warning for E_WARNING and E_USER_WARNING
• PHPUnit_Framework_Error for all others

您可以像其他任何例外一样捕获并期待这些.

You can catch and expect these as you would any other exception.

/**
 * @expectedException PHPUnit_Framework_Error_Warning
 */
function testNegativeNumberTriggersWarning() {
    $fixture = new someClass;
    $fixture->loadValue(-1);
}

这篇关于如何在PHPUnit中捕获PHP警告的文章就介绍到这了，希望我们推荐的答案对大家有所帮助，也希望大家多多支持IT屋！