Dill.detect.children对象类型 [英] Dill.detect.children object types

问题描述

Dill.detect.children需要两个参数； obj和objtype.

Dill.detect.children requires two arguments; obj and objtype.

检查我可以调用的 audiofile 对象:

Inspecting an audiofile object I can call:

dill.detect.children(audiofile, object)
dill.detect.children(audiofile, dict)
dill.detect.children(audiofile, list)

返回没有错误.

但是寻找实例方法呢?

type(audiofile.save)

返回

instancemethod

尝试

dill.detect.children(audiofile, instancemethod)

返回

NameError: name 'instancemethod' is not defined

尝试

dill.detect.children(audiofile, 'instancemethod')

返回

TypeError: isinstance() arg 2 must be a class, type, or tuple of classes and types

这不应该返回与调用dir(audiofile)类似的结果吗?

Shouldn't this return similar results to calling dir(audiofile)?

推荐答案

使用 types.MethodType :

types.MethodType

用户定义的类实例的方法类型.

The type of methods of user-defined class instances.

>>> import types
>>> print types.MethodType
<type 'instancemethod'>
>>> p = Process()
>>> type(p.start) == types.MethodType
True

但是，我认为dill.detect.children并没有您认为的那样.它的文档字符串说:

However, I don't think dill.detect.children does what you think it does. Its docstring says:

children(obj, objtype, depth=1, ignore=())
    Find the chain of referrers for obj. Chain will start with obj.

    objtype: an object type or tuple of types to search for
    depth: search depth (e.g. depth=2 is 'grandparents')
    ignore: an object or tuple of objects to ignore in the search

    NOTE: a common thing to ignore is all globals, 'ignore=globals()'

    NOTE: repeated calls may yield different results, as python stores
    the last value in the special variable '_'; thus, it is often good
    to execute something to replace '_' (e.g. >>> 1+1).

这与在obj上找到与类型objtype匹配的所有属性"不同，它至少出现是您期望它执行的操作.

This is not the same as "find all attributes on obj that match type objtype", which it at least appears is what you're expecting it to do.

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