matplot饼图:水平旋转标签 [英] matplot pie: rotate labels horizontally

问题描述

使用matplot通过以下代码创建一个小量规:

Using matplot to create a little gauge with the code below:

    group_size=[10,10,10,10,10,50]
    labels=['AAAA','BBBB','CCCC','DDDD','EEEE','']
    fig, ax = plt.subplots()
    ax.axis('equal')
    pie = ax.pie(group_size, radius=2.2, colors=['k'] ,startangle=180,counterclock=False)
    pie2 = ax.pie([10,10,10,10,10,50], radius=2,  labeldistance=0.7, labels=labels, rotatelabels = 270,
startangle=180,counterclock=False)
    plt.show()

我正在尝试使标签水平移动并像这样与每个楔形的中点对齐(但要与楔形内部的文本对齐):

I am trying to get the labels to go horizontally and align with the midpoint of each wedge like this (but with the text inside the wedges):

使用rotatelabel = True，我得到以下信息:

Using rotatelabel=True, I get the following:

关于如何实现图形标签水平旋转的任何想法?

Any ideas on how I can achieve the horizontal rotation of the labels for the graph?

推荐答案

您需要手动旋转饼图标签.为此，您可以遍历标签并根据需要设置旋转角度.

You need to rotate the pie labels manually. To this end you may loop over the labels and set the rotation to your needs.

group_size=[10,10,10,10,10,50]
labels=['AAAA','BBBB','CCCC','DDDD','EEEE','']
fig, ax = plt.subplots()
ax.axis('equal')
pie = ax.pie(group_size, radius=2.2, colors=['k'] ,startangle=180,counterclock=False)
pie2 = ax.pie([10,10,10,10,10,50], radius=2,  labeldistance=0.9, labels=labels, 
              rotatelabels =True, startangle=180,counterclock=False)

plt.setp(pie2[1], rotation_mode="anchor", ha="center", va="center")
for tx in pie2[1]:
    rot = tx.get_rotation()
    tx.set_rotation(rot+90+(1-rot//180)*180)

plt.show()

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