如何从Python3中的像素值列表创建图像? [英] How to create image from a list of pixel values in Python3?
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问题描述
如果我有以下格式的图像的像素行列表,怎么获得图像?
If I have a list of pixel rows from an image in the following format, how would get the image?
[
[(54, 54, 54), (232, 23, 93), (71, 71, 71), (168, 167, 167)],
[(204, 82, 122), (54, 54, 54), (168, 167, 167), (232, 23, 93)],
[(71, 71, 71), (168, 167, 167), (54, 54, 54), (204, 82, 122)],
[(168, 167, 167), (204, 82, 122), (232, 23, 93), (54, 54, 54)]
]
推荐答案
PIL
和numpy
是您的朋友在这里:
PIL
and numpy
are your friends here:
from PIL import Image
import numpy as np
pixels = [
[(54, 54, 54), (232, 23, 93), (71, 71, 71), (168, 167, 167)],
[(204, 82, 122), (54, 54, 54), (168, 167, 167), (232, 23, 93)],
[(71, 71, 71), (168, 167, 167), (54, 54, 54), (204, 82, 122)],
[(168, 167, 167), (204, 82, 122), (232, 23, 93), (54, 54, 54)]
]
# Convert the pixels into an array using numpy
array = np.array(pixels, dtype=np.uint8)
# Use PIL to create an image from the new array of pixels
new_image = Image.fromarray(array)
new_image.save('new.png')
使用numpy
制作随机像素图像有点有趣:
A little fun with numpy
to make an image of random pixels:
from PIL import Image
import numpy as np
def random_img(output, width, height):
array = np.random.random_integers(0,255, (height,width,3))
array = np.array(array, dtype=np.uint8)
img = Image.fromarray(array)
img.save(output)
random_img('random.png', 100, 50)
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