从stderr重定向到另一个文件描述符 [英] Redirect FROM stderr to another file descriptor
本文介绍了从stderr重定向到另一个文件描述符的处理方法,对大家解决问题具有一定的参考价值,需要的朋友们下面随着小编来一起学习吧!
问题描述
我的程序调用打印到stderr的库函数.我想进行干预,以便将对文件描述符2的所有写调用都发送到其他地方.
My program calls library functions which print to stderr. I want to intervene so that all write calls to file descriptor #2 will instead get sent to somewhere else.
这是我的第一次尝试:
bool redirect_stderr (int fd)
{
return dup2 (2, fd) > 0;
}
在这里,从open("/foo/bar",O_APPEND|O_CREAT)
此函数返回true后,std::cerr<<"blah"
转到终端而不是文件.
After this function returns true, std::cerr<<"blah"
goes to the terminal and not to the file.
我在做什么错了?
谢谢.
更新
谢谢,拉尔曼兄弟,但我还没到那里...
Thanks, larsmans, but I'm not there yet...
void redirect_stderr_to (const char * output_file)
{
int fd = open (output_file, O_APPEND | O_CREAT, S_IRUSR | S_IWUSR);
if (fd < 0) {
throw RUNTIME_ERROR;
}
else {
if (-1 == dup2 (fd, STDERR_FILENO))
throw RUNTIME_ERROR;
std :: cout << (std::cerr ? "Fine\n" : "Bad\n");
char x [100];
std :: cerr
<< "Output to " << getcwd (x, 100) << " / " << output_file
<< " yields " << fd << " errno: " << errno << "\n";
std :: cout << (std::cerr ? "Fine\n" : "Bad\n");
}
}
此输出
Fine
Bad
到标准输出,给定文件为空. (如果不存在,则会正确创建.)
to stdout and the given file is empty. (It is correctly created if it doesn't exist.)
推荐答案
您颠倒了参数:是
dup2(from_fd, to_fd)
即
dup2(fd, 2)
(请参见 POSIX.2008 或您的联机帮助页.)
(see POSIX.2008 or your manpages.)
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