Windows cmd将一个命令的输出作为参数传递给另一命令 [英] Windows cmd pass output of one command as parameter to another

问题描述

在Linux中，可能无法做到这一点:

In linux it is possible t do this:

git diff $(git status -s -b | sed -n '2p' | cut -d' ' -f2-)

或更简单的情况

ls $(pwd) 

问题是如何在Windows中实现相同的目标? (不使用批处理文件，在命令提示符下使用一个衬板).并非所有命令都支持管道，因此我们如何评估一个并将结果作为参数传递给另一个?

The question is how can I achieve the same in windows? (not using a batch file, a one liner in command prompt). Not all commands support piping so how can we evaluate one and pass result as parameter to another?

我已经尝试了管道和<和>，但是没有用.

I've tried piping and < and > but none work.

git diff < (git status -s -b | sed -n '2p' | cut -d' ' -f2-) 

尝试自己尝试获取文件.而且|也不起作用，因为git diff不支持

Try that yourself it expects a file. And | doesn't work either as git diff doesn't support it

git status -s -b | sed -n '2p' | cut -d' ' -f2- | git diff // results in illegal seek

推荐答案

cmd中没有$运算符.
重定向运算符(<，>，>>)期望文件或流句柄.
管道|将命令的标准输出传递到另一个命令的标准输入中.

There is no $ operator in cmd.
Redirection operators (<, >, >>) expect files or stream handles.
A pipe | passes the standard output of a command into the standard input of another one.

for /F循环可以捕获命令的输出，并将其提供给变量引用(在示例中为%A)；请参阅以下代码:

A for /F loop however is capable of capturing the output of a command and providing it in a variable reference (%A in the example); see the following code:

for /F "usebackq delims=" %A in (`git status -s -b ^| sed -n '2p' ^| cut -d' ' -f2-`) do git diff %A

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