如何获得YQL的格式化视图? [英] How to get the formatted view of YQL as result?

问题描述

YQL仅在树形视图中给出结果.有什么办法可以在格式化视图中获得结果?

YQL gives out result only in tree view. Is there any way to get the result in Formatted view??

推荐答案

使用XSLT样式表创建带格式的视图.这是RSS供稿的示例:

Use an XSLT stylesheet to create a formatted view. Here is an example for an RSS feed:

<?xml version="1.0" encoding="utf-8"?>
<xsl:stylesheet version="1.0" xmlns:xsl="http://www.w3.org/1999/XSL/Transform">
<xsl:output method="XML" encoding="utf-8"
doctype-public="-//W3C//DTD XHTML 1.0 Transitional//EN"
doctype-system=http://www.w3.org/TR/xhtml1/DTD/xhtml1-transitional.dtd
indent="yes"/>

<xsl:template match='//channel'>
<page>
<content>
<module>
<header layout="simple">
<layout-items>
<block class="title">YDN Widget</block>
</layout-items>
</header>
</module>
<xsl:apply-templates select="item" />
</content>
</page>
</xsl:template>

<xsl:template match="item">
<placard layout="card" class="link">
<layout-items>
<image resource="ybang"/>
<block class="title"><xsl:value-of select="title"/></block>
<block class="description"><xsl:value-of select="pubDate"/></block>
<block class="subtext"><xsl:value-of select="category"/></block>
</layout-items>
<load resource="{link}" event="activate"/>
</placard>
</xsl:template>
</xsl:stylesheet>

使用以下YQL语法进行引用:

Referenced using the following YQL syntax:

select * from xslt where url="//foo.rss" and stylesheet="//bar.xsl"

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