PostgreSQL说“返回和sql元组描述不兼容". [英] PostgreSQL says "return and sql tuple descriptions are incompatible"

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问题描述

我有以下数据:

ID  CLASS   VALUE
1   NHB    700905.7243
1   HBW    164216.1311
1   HBO    700905.7243
2   NHB    146023.3792
2   HBW    89543.2972
2   HBO    82152.072
3   NHB    1409818.328
3   HBW    220430.7922
3   HBO    323512.9391
4   NHB    48711.3814
4   HBW    163385.1575
4   HBO    363352.3441

我想重新组织为:

ID     HBO             HBW              NHB
1   700905.7243    164216.1311      700905.7243
2   82152.072      89543.2972       146023.3792
3   323512.9391    220430.7922      1409818.328
4   363352.3441    163385.1575      48711.3814

请注意,HBW,HBO和NHB列中的值为总计(总和).

Please note that the values in columns HBW, HBO and NHB are totals (sum).

这是我用来创建输出的脚本:

Here is the script I am using to create the output:

-- CREATE EXTENSION tablefunc;

SELECT *
FROM  CROSSTAB
(
    'SELECT _tlfd.id,   
    _tlfd."class",
    _tlfd."value"
    FROM public._tlfd
    WHERE _tlfd."class" = ''HBW'' or _tlfd."class" = ''HBO'' or _tlfd."class" = ''NHB'' 
    ORDER BY 1,2'
) 
    AS
(
    "class" int, 
    "HBW" text,
    "HBO" text,
    "NHB" text,
    --"Purpose" varchar, 
    "value" double precision
);

运行脚本时出现此错误:

When I run the script I get this error:

ERROR:  return and sql tuple descriptions are incompatible. 

我不确定这意味着什么以及如何纠正错误.有人可以让我知道吗

I am not sure what this means and how to correct the error. Can someone please let me know:

  1. 我在脚本中做错什么了?
  2. 我的脚本会产生所需的输出吗?

推荐答案

这在Postgres 9.3上对我有效:

This works for me on Postgres 9.3:

SELECT *
    FROM  crosstab (
        $$SELECT id, class, "value"
         FROM   _tlfd
         WHERE  class = ANY ('{HBW, HBO, NHB}')
         ORDER  BY 1,2$$
    ) 
        AS
    t ( class int,                   -- needs a table alias!
        "HBW" float8,                -- resulting columns are double precision!
        "HBO" float8,
        "NHB" float8
        -- "value" double precision  -- column does not exist in result!
    );

产生所需的输出.我无法提供SQLfiddle,因为无法在其中安装其他模块.

Produces the desired output. I can't provide an SQLfiddle, since one cannot install additional modules there.

  • 表别名(粗体 t )
  • 已删除的剩余列"value"
  • 数据列的正确数据类型(double precision又称float8)
  • the table alias (bold t)
  • the removed surplus column "value"
  • the correct data type for your data columns (double precision a.k.a. float8)

其余的只是口味和风格的问题.我不会使用value作为列名,因为它是

The rest is a matter of taste and style. I wouldn't use value as column name though, since it is a reserved word in SQL.

此相关答案的详细信息:
PostgreSQL交叉表查询

Details in this related answer:
PostgreSQL Crosstab Query

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