包含％符号的字符串中的Python占位符 [英] Python placeholders in strings containing the % symbol

问题描述

我希望能够在已经包含%符号的字符串中使用占位符.例如，我希望能够迭代打开多个URL，因为我的URL已经包含%符号，例如url:

I want to be able to use a placeholder in a string that already contains a % symbol. For instance, I would like to be able to iterate to open multiple URLs by my URL already contains a % symbol, example url:

http://www.example.com/BLABLA%123BLABLApage=1

为此，我想用一个占位符(%d)替换数字1，但是代码似乎被占位符前面的%的存在所迷惑.

To do so, I want to replace the number 1 by a placeholder (%d), but the code seems to be confused by the presence of the % that comes before the placeholder.

推荐答案

您可以通过将%加倍来对其进行转义:

You can escape % by doubling it:

>>> 'http://www.example.com/BLABLA%%123BLABLApage=%d' % (1,)
'http://www.example.com/BLABLA%123BLABLApage=1'

或者，使用 str.format() 格式设置:

Alternatively, use str.format() formatting instead:

>>> 'http://www.example.com/BLABLA%123BLABLApage={:d}'.format(1)
'http://www.example.com/BLABLA%123BLABLApage=1'

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