Play Framework网络服务教程Scala [英] Play Framework webservice tutorial scala
问题描述
我是新手!和scala,我正拼命寻找有关如何实现Web服务的逐步教程.该文档非常糟糕,我找不到有帮助的东西.
I'm pretty new to Play! and scala and i'm searching desperatly for a good step by step tutorial on how to implement a webservice. the documentation is pretty poor and i can't find something that helps.
ps:我已经完成了playframework网站上给出的示例,这对理解框架很有帮助,但是我对scala的了解是这里的最大障碍.
ps: i have already done the exemple given in the playframework web site it helped a lot for the understanding of the framework but my knowledge to scala is the big obstacle here.
推荐答案
好吧,我认为这就是我想要的.首先让我们假设我们想要一个RESTfull Web服务,该服务返回有关用户的信息.我们按照以下方式创建用户类
Well i think this is what i wanted. First lets assume that we want a RESTfull webservice that returns informations about a user. we create the user class as following
case class User() {
val id= 1
val name = "john"
val score = 8.5
}
然后我们制作如下的控制器
then we make the controller which is as follow
object Application extends Controller {
def sum() = Action {
val user = new User
val json = Json.generate(user)
Ok(json).as("application/json")
}
}
别忘了为Json添加导入文件,该导入文件为import com.codahale.jerkson.Json
and don't forget to add the import for Json which is import com.codahale.jerkson.Json
对于路由,将以下行添加到您的route
文件中:
For the route add the following line to your route
file:
GET /sum controllers.Application.sum
结果应类似于
{
"id":1,
"name":"john",
"score":8.5
}
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