生成R个情节图的列表并将其传递给子图 [英] Generate list of R plotly plots and pass it to subplot

问题描述

通常在使用基本R图形(使用par(mfrow=c(nr,nc)))时在for循环中生成子图.我试图通过生成一系列绘图并将它们保存到列表中以稍后传递给subplot函数，来与plotly做类似的事情.但是，由于我不明白的原因，在循环的结尾，列表的所有元素似乎都包含相同的图(最后一个图).如果我在循环内的列表中打印每个图(在下面的示例中取消注释以print开头的行)，则这些图看起来很好).我不太了解发生了什么.有人可以解释这种意外行为或在下面的示例代码中指出问题吗?

I usually generate subplots in a for loop when using base R graphics (using par(mfrow=c(nr,nc))). I'm trying to do something similar with plotly, by generating a series of plots and saving them to a list to be later passed to the subplot function. However, for reasons that I don't understand, at the end of the loop all the elements of the list seem to contain the same plot (the last one). If I print each plot in the list within the loop (uncommenting the line starting with print in the example below), then the plots seem fine). I don't really understand what's going on. Could someone explain this unexpected behavior or point out issues with my example code below?

library(plotly)
plotList = list()
plotListNames = c("p1", "p2", "p3")

for (i in 1:3){
    x = rnorm(10)
    y = rnorm(10)
    thisName = plotListNames[i]
    plotList[[thisName]] = plot_ly(x=x,y=y, name=thisName)
    ##print(plotList[[thisName]]
}

sbp = subplot(plotList[["p1"]], plotList[["p2"]], plotList[["p3"]])
print(sbp)

推荐答案

尝试一下:

plotList[[thisName]] =  plotly_build(plot_ly(x=x,y=y, name=thisName))

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