在Oracle中从十六进制编码的CLOB转换为BLOB [英] Convert from hex-encoded CLOB to BLOB in Oracle

问题描述

我在CLOB中存储了一些十六进制形式的大型二进制内容，并希望将其转换为BLOB，其中十六进制代码是实际的二进制字节编码:

I have some large binary content in hex form stored in a CLOB and want to convert that to a BLOB where the hex code is actual binary byte encoding:

DECLARE

  -- This would be my 8 byte hex-encoded binary content. Real content is much bigger
  c CLOB := 'cafebabe12345678';
  b BLOB;
BEGIN

  -- Need the implementation of this function
  b := hex_to_blob(c);
END;
/

使用PL/SQL在Oracle中最简单的方法是什么?

What's the easiest way to do that in Oracle, using PL/SQL?

推荐答案

所需的功能可能如下所示:

The desired function could look like this:

CREATE OR REPLACE
FUNCTION hex_to_blob (hex CLOB) RETURN BLOB IS
  b BLOB                := NULL;
  s VARCHAR2(4000 CHAR) := NULL;
  l NUMBER              := 4000;
BEGIN
  IF hex IS NOT NULL THEN
    dbms_lob.createtemporary(b, FALSE);

    FOR i IN 0 .. LENGTH(hex) / 4000 LOOP
      dbms_lob.read(hex, l, i * 4000 + 1, s);
      dbms_lob.append(b, to_blob(hextoraw(s)));
    END LOOP;
  END IF;

  RETURN b;
END hex_to_blob;

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