如何使用逗号分隔的字符串和逗号之间的(可能)空白字段按顺序拆分字符串 [英] How to split a string in order with a comma-separated string and (possible) empty fields between commas
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问题描述
我需要在Oracle PL/SQL中以逗号分隔的字符串顺序分割,包括空字段作为无"值. 这是一个包含6个字段的示例,但可以包含更多或更少的字段
I need to split a string in Oracle PL/SQL with comma-separated in order, including empty fields as "none" value. This is an example with 6 fields but can have more or less fields
line varchar2(100) := "value1;value2;;;value5;value6;";
WITH test AS (SELECT line FROM DUAL)
SELECT NVL(REGEXP_SUBSTR (line, '[^;]+', 1, ROWNUM),'none') as SPLIT
FROM test
CONNECT BY LEVEL <= LENGTH (REGEXP_REPLACE (line, '[^;]+'));
输出:
value1
value2
value5
value6
none
none
理想的输出:
value1
value2
none
none
value5
value6
推荐答案
with test as (select 'value1;value2;;;value5;value6;' line from dual)
select nvl(regexp_substr (line, '([^;]*);', 1, rownum, null, 1), 'none') as split
from test
connect by level <= regexp_count (line, ';');
SPLIT
------------------------------
value1
value2
none
none
value5
value6
6 rows selected.
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