为什么我的指针在C ++中输出一个字符串而不是一个内存地址? [英] Why does my pointer output a string and not a memory address in C++?

问题描述

我正在研究使用指针的字符串类，但是在理解我的print函数在这里如何工作时遇到了一些困难.具体来说，为什么cout << pString输出字符串而不是它指向的动态数组的内存地址?我的理解是变量pString是一个指针.

I'm working on a string class that employs pointers and I'm just having some difficulty in understanding how my print function works here. Specifically, why does cout << pString output the string and not the memory address of the dynamic array that it's pointing to? My understanding was that the variable pString was a pointer.

class MyString
{
    public:
        MyString(const char *inString);
        void print();
    private:
        char *pString;
};


MyString::MyString(const char *inString)
{
    pString = new char[strlen(inString) + 1];
    strcpy(pString, inString);
}

void MyString::print()
{
    cout << pString;
}

int main( )
{
    MyString stringy = MyString("hello");
    stringy.print();
    return 0;
}

推荐答案

这是因为<<运算符已被重载以处理char*的大小写并将其打印为字符串.与地址相反(其他指针就是这种情况).

This is because the << operator has been overloaded to handle the case of a char* and print it out as a string. As opposed to the address (which is the case with other pointers).

我可以肯定地说，这样做是为了方便-使其易于打印出字符串.

I think it's safe to say that this is done for convenience - to make it easy to print out strings.

因此，如果要打印出地址，则应将指针投射到void*.

So if you want to print out the address, you should cast the pointer to a void*.

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