为什么指针声明中的星号特定于标识符而不是数据类型? [英] Why is the asterisk in a pointer declaration specific to the identifier and not the data type?

问题描述

愚蠢的问题，但尝试掌握潜在的机制/哲学以巩固我的理解.

Silly question, but trying to grasp the underlying mechanics/philosophy to solidify my understanding.

int myInt; // declares a variable of type integer, named myInt. Intuitive.
int* myPtr; // declares a variable of type pointer-to-integer. Also intuitive.

int myInt2, myInt3; // two more integer variables.. yay!! This makes sense.
// so the pattern is [type] [identifier] <,more-identifiers>;

int* myInt4, myInt5; // an int pointer then an integer. Brain hurts!

推荐答案

TL; DR-这就是C语法设计的工作方式.

TL;DR - that is how C syntax is designed to work.

*被认为是附加变量，因为它定义了变量的类型，而不是 datatype .对象的类型应该是对象本身的属性，因此考虑该属性的 identifier 与该对象(变量)相关是很有意义的.

The * is considered attached to the variable, because, it defines the type of the variable, not the datatype. The type of an object is supposed to be a property of the object itself, so it makes sense to consider the identifier of the property is associated with the object(variable).

为澄清起见，我们说int * p;的意思是说p是 pointer 类型的变量，它指向int.因此，将*附加到变量而不是数据类型是有道理的.

To clarify, by saying int * p;, we mean to say, p is a variable of type pointer which points to an int. So, it makes sense to attach the * to the variable, rather than to the datatype.

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