C:无法使用void *类型的右值初始化变量 [英] C: Cannot initialize variable with an rvalue of type void*

问题描述

我有以下代码:

int *numberArray = calloc(n, sizeof(int));

我不明白为什么会收到以下错误消息.

And I am unable to understand why I receive the following error.

Cannot initialize a variable of type 'int *' with an rvalue of type 'void *'`.

谢谢.

推荐答案

编译器的错误消息非常清晰.

The compiler's error message is very clear.

calloc的返回值为void*.您正在将其分配给类型为int*的变量.

The return value of calloc is void*. You are assigning it to a variable of type int*.

对于C程序来说可以，但是对于C ++程序则不能.

That is ok with a C program, but not with a C++ program.

您可以将该行更改为

int* numberArray = (int*)calloc(n, sizeof(int));

但是，更好的选择是使用new运算符分配内存.毕竟，您正在使用C ++.

But, a better alternative will be to use the new operator to allocate memory. After all, you are using C++.

int* numberArray = new int[n];

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