node * node1与node * node1有什么区别? [英] What is the difference node *node1 vs node* node1?

问题描述

我有1个节点:

struct node
    {
        int key;
        struct node *left, *right;
    };

node  *node1

vs

node*  node1

?

推荐答案

没有typedef，这两个声明都是非法的.

Without a typedef, both the declarations are illegal.

带有typedef之类的

 typedef struct node node;

就位，没有区别.这两个语句都声明了一个指向node的类型的变量node1. (注意:不过，您仍然需要终止的; ).

in place, there's no difference. Both the statements declare a variable node1 of type pointer to node. (Note: You'll still be needing the terminating ;, though).

这是一个选择问题，但是某些人(包括我在内)更喜欢将指针表示法附加到变量上，以避免在出现多个变量声明的情况下产生误解，例如

It's a matter of choice, but some (including me) prefer to attach the pointer notation to the variable, to avoid misunderstanding, in case of multiple variable declaration, like

 node *p, q;

其中，p是指针类型，但q不是指针类型.

where, p is pointer type, but q is not.

像这样写

 node* p, q;

可能产生一种幻觉，即p和q都是指针类型，本质上它们是不是.

may create the illusion that p and q both are of pointer type, where, in essence, they are not.

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