Android:动态传递模型类以进行回调 [英] Android:dynamically pass model class to retrofit callback
问题描述
为了将json响应映射到pojo，通常我们会这样做
In retrofit to map json response to pojo usually we do this
@POST
Call<User> getDataFromServer(@Url String url, @Body HashMap<String,Object> hashMap);
ApiCalls api = retrofit.create(ApiCalls.class);
Call<User> call = api.getDataFromServer(StringConstants.URL,hashMap);
call.enqueue(new Callback<User>() {
//Response and failure callbacks
}
其中User是我的Pojo类. 但是对于其他每个请求，我都需要制作不同的pojo并编写相同的代码进行改造调用.我想制作一个用于调用api的方法，并将相应的pojo类传递给改造调用.像这样
where User is my Pojo class. But for every other request i need to make different pojo and write same code for retrofit call.I want to make a single method for calling api and pass the respective pojo class to retrofit call. like this
ApiCalls api = retrofit.create(ApiCalls.class);
Call<*ClassPassed*> call = api.getDataFromServer(StringConstants.URL,hashMap);
call.enqueue(new Callback<*ClassPassed*>() {
//Response and failure callbacks
}
所以现在我可以将任何pojo类都转换为单个方法并获取响应.这只是为了避免一次又一次地重写相同的代码.
so now i can any pojo class to single method and get the response.This is just to avoid rewriting the same code again and again.is this possible
更新 详细说明:
假设我需要提出两个请求.第一个是获取userDetails，另一个是PatientDetails.So，我必须创建两个模型类User和Patient. 因此，在翻新api中，我会遇到类似的情况
Suppose I need to make two requests. First one is to get userDetails and the other is patientDetails.So i have to create two model classes User and Patient. So in retrofit api i'll be having something like this
@POST
Call<User> getDataFromServer(@Url String url, @Body HashMap<String,Object> hashMap);
@POST
Call<Patient> getDataFromServer(@Url String url, @Body HashMap<String,Object> hashMap);
在我的FragmentUser和FragmentPatient类中，我将这样做
and in my FragmentUser and FragmentPatient class i'll be doing this
ApiCalls api = retrofit.create(ApiCalls.class);
Call<User> call = api.getDataFromServer(StringConstants.URL,hashMap);
call.enqueue(new Callback<User>() {
//Response and failure callbacks
}
ApiCalls api = retrofit.create(ApiCalls.class);
Call<Patient> call = api.getDataFromServer(StringConstants.URL,hashMap);
call.enqueue(new Callback<Patient>() {
//Response and failure callbacks
}
但是这里的代码只是因为不同的pojo类而重新出现，我需要在其他片段中针对不同的请求重复相同的代码. 因此，我需要制作一个通用方法，使其可以接受任何pojo类，然后从片段开始，我将传递要映射的pojo.
but here the code is repaeting just beacuse of different pojo classes.I need to repeat the same code in every other fragments for different requests. So i need to make a generic method where it can accept any pojo class and then from fragment i'll be just passing the pojo to be mapped.
推荐答案
Android:动态传递模型类以进行回调
Android:dynamically pass model class to retrofit callback
您可以通过2种方法来实现此目的.........
There is 2 ways you can do this .........
1.泛型
2.将所有POJO合并为一个......
泛型
在泛型中，您必须将方法与类一起传递.请看例子.....
In the Generics you have to pass the method with the class. pleas have look on example .....
ApiCalls api = retrofit.create(ApiCalls.class);
Call<User> call = api.getDataFromServer(StringConstants.URL,hashMap);
callRetrofit(call,1);
public static <T> void callRetrofit(Call<T> call,final int i) {
call.enqueue(new Callback<T>() {
@Override
public void onResponse(Call<T> call, Response<T> response) {
if(i==1){
User user = (User) response.body(); // use the user object for the other fields
}else if (i==2){
Patient user = (Patient) response.body();
}
}
@Override
public void onFailure(Call<T> call, Throwable t) {
}
});
}
注意:-在翻新呼叫上方，键入您的回复为YOUR OBJECT，这样您就可以访问其字段和方法
NOTE:- Above retrofit call TypeCast your response into YOUR OBJECT, so you can access its field and methods
将所有POJO合并为一个
它非常易于使用.您必须将所有POJO类合并为一个，并在Retrofit中使用它们.请看下面的例子....
It is very easy to use . You have to combine your all POJO class into one and use them inside the Retrofit. please have look on below example ....
我有两个API登录名和一个用户...
I have two API login and user......
在Login API中，我得到了这样的JSON响应...
{成功":是，消息":验证成功"}
{ "success": True, "message": "Authentication successful"}
在JSON之上，POJO如下所示
public class LoginResult{
private String message;
private boolean success;
//constructor , getter and setter
}
和翻新呼叫如下所示...
call.enqueue(new Callback<LoginResult>() {
@Override
public void onResponse(Call<LoginResult> call, Response<LoginResult> response) {
}
@Override
public void onFailure(Call<LoginResult> call, Throwable t) {
}
});
在用户API中，我得到了这样的JSON响应.. .
{名称":"sushildlh"，地点":海得拉巴"}
{"name": "sushildlh", "place": "hyderabad"}
在JSON之上，POJO如下所示
public class UserResult{
private String name;
private String place;
//constructor , getter and setter
}
和翻新呼叫如下所示...
call.enqueue(new Callback<UserResult>() {
@Override
public void onResponse(Call<UserResult> call, Response<UserResult> response) {
}
@Override
public void onFailure(Call<UserResult> call, Throwable t) {
}
});
只需将以上两个JSON响应合并为一个.....
public class Result{
private String name;
private String place;
private String message;
private boolean success;
//constructor , getter and setter
}
并在您的API调用中使用Result ......
call.enqueue(new Callback<Result>() {
@Override
public void onResponse(Call<Result> call, Response<Result> response) {
}
@Override
public void onFailure(Call<Result> call, Throwable t) {
}
});
注意:-您直接组合2 POJO类并对其进行访问. (如果您的响应非常大，并且如果某些KEY的变量类型相同，则重复操作会非常复杂).
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