到达特定页面后，弹出浏览器返回到父浏览器 [英] Popup browser back to parent browser after a certain page is reached

问题描述

我有一个弹出窗口(我在必要时使用)，可以通过单击链接打开.我让用户浏览一系列页面选择属性，然后将其发送到购物车.

I have a popup (which I used by necessity) that is opened on a link click. I have the user going through a series of pages picking attributes to then be sent to a shopping cart.

我的问题:用户到达选择过程的结尾后，我想终止打开的弹出窗口，并将请求发送回原始浏览器(父级)，以便用户可以结帐.

My problem: After the user reaches the end of the selection process i want to kill the open popup and send the request back to the original browser (parent) so the user can checkout.

知道我将如何做吗?

推荐答案

Javascript:在子(弹出)窗口中.

Javascript: in the child (popup) window.

window.opener.location = 'page.html";
window.close();

这是您要找的吗?

这篇关于到达特定页面后，弹出浏览器返回到父浏览器的文章就介绍到这了，希望我们推荐的答案对大家有所帮助，也希望大家多多支持IT屋！