pthread_cond_signal()仅释放一个线程? [英] pthread_cond_signal() release exactly one thread?

问题描述

pthread_cond_signal是否完全取消阻塞一个线程?如果没有，它将释放多个线程怎么办?规格说明如下:

Does pthread_cond_signal unblock exactly one thread? If not, what will be the case it releases more than one thread? The specification says as follows:

pthread_cond_signal()函数应解除对以下至少一项的阻止: 在指定的条件变量cond上阻塞的线程(如果 任何线程都在cond上被阻止.)

The pthread_cond_signal() function shall unblock at least one of the threads that are blocked on the specified condition variable cond (if any threads are blocked on cond).

推荐答案

pthreads规范允许实现中的虚假唤醒".例如，请参见pthread_cond_signal和pthread_cond_wait的假设实现，规范，仅允许这种情况.

The pthreads specification allows for "spurious wakeups" in an implementation. See, for example, the hypothetical implementation of pthread_cond_signal and pthread_cond_wait sketched in the specification that allows for just this condition.

伪唤醒的可能性是为什么总是将某些谓词与条件相关联，并在唤醒时检查该谓词的原因.

The possibility of spurious wakeups is why one always associates some predicate with a condition, and checks that predicate upon wakeup.

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