Spring MVC + Zepto POST中的"Access-Control-Allow-Origin"错误 [英] 'Access-Control-Allow-Origin' error in Spring MVC + Zepto POST

问题描述

我正在尝试将JSON对象发布到我的Spring MVC控制器，但是我只收到一个Access-Control-Allow-Origin错误.

I'm trying to POST a JSON object to my Spring MVC controller, but I only receive an Access-Control-Allow-Origin error.

我的控制器:

@RequestMapping(value= "/add", method = RequestMethod.POST, headers = {"content-type=application/json"})
public @ResponseBody Reponse addUser(Model model, @RequestBody @Valid @ModelAttribute("user") User user, BindingResult result) {
    if (result.hasErrors()) {
        Reponse error = new Reponse();
        // etc......
        return error;
    } else {
        return service.addUser(user);
    }
}

我的Zepto帖子:

this.addUser = function (valeur, callback) {
    $.ajax({
        type: 'POST',
        url: 'http://127.0.0.1:8080/AgenceVoyage/user/add',
        data: JSON.stringify({"mail" : "[e-mail]" , "password" : "titi"}),
        dataType: "json",
        contentType: "application/json",

        success: function(data) {
            if(data.reponse == "OK") {
                window.location = "main.html";
            } else {
                alert("PROBLEM");
            }
        },

        error: function(xhr, type) {
            alert("ERROR");
        }
    });
};

我尝试在POST请求中没有字符串化，在@RequestMapping中没有标题.

I tried with no stringify in POST request, with no headers in @RequestMapping.

我的结果:

OPTIONS http://127.0.0.1:8080/AgenceVoyage/user/add 不 请求中存在"Access-Control-Allow-Origin"标头 资源.因此，不允许来源' http://localhost:9000 使用权. zepto.min.js:2 XMLHttpRequest无法加载

OPTIONS http://127.0.0.1:8080/AgenceVoyage/user/add No 'Access-Control-Allow-Origin' header is present on the requested resource. Origin 'http://localhost:9000' is therefore not allowed access. zepto.min.js:2 XMLHttpRequest cannot load

推荐答案

我找到了解决方案:

首先，创建一个新的过滤器，该过滤器将设置标头响应:

Firstly, create a new filter, which will set the header response :

    @Component
public class SimpleCORSFilter implements Filter {

    public void doFilter(ServletRequest req, ServletResponse res, FilterChain chain) throws IOException, ServletException {
        HttpServletResponse response = (HttpServletResponse) res;
        response.setHeader("Access-Control-Allow-Origin", "*");
        response.setHeader("Access-Control-Allow-Methods", "POST, GET, OPTIONS, DELETE");
        response.setHeader("Access-Control-Max-Age", "3600");
        response.setHeader("Access-Control-Allow-Headers", "x-requested-with");
        chain.doFilter(req, res);
    }

    public void init(FilterConfig filterConfig) {}

    public void destroy() {}

}

然后，在您的web.xml中添加以下行:

After that, in your web.xml add those lines :

 <filter>
  <filter-name>cors</filter-name>
  <filter-class>MY.PACKAGE.SimpleCORSFilter</filter-class>
 </filter>

 <filter-mapping>
  <filter-name>cors</filter-name>
  <url-pattern>/*</url-pattern>
 </filter-mapping>

这一切！

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