如何创建通讯录和联系人 [英] How to create a addressbook and contacts

问题描述

我为通讯录和联系人创建了一个代码，其中显示了联系人。它工作正常，但突然出现运行时错误。由于我是ios的新手，我找不到错误可以在其中找到任何人

I have created a code for Addressbook and contacts where display the contacts.It was working properly but suddenly getting Run time error .As I'm new to ios .I'm not able to find the error can any one in the Stack Overflow tell the error.

- (void)viewDidLoad
 {
 [super viewDidLoad];
 self.view = [[UIView alloc] initWithFrame:[[UIScreen mainScreen] applicationFrame]];
 self.view.backgroundColor = [UIColor yellowColor];
 self.navigationItem.leftBarButtonItem = [[[UIBarButtonItem alloc]initWithBarButtonSystemItem:UIBarButtonSystemItemCancel target:self action:@selector(gotohomepage:)]autorelease];
   ABPeoplePickerNavigationController *picker = [[ABPeoplePickerNavigationController alloc] init];
[[picker navigationBar] setBarStyle:UIBarStyleBlack];
picker.peoplePickerDelegate = self;
// Display only a person's phone, email, and birthdate
NSArray *displayedItems = [NSArray arrayWithObjects:[NSNumber numberWithInt:kABPersonPhoneProperty],nil];


picker.displayedProperties = displayedItems;
[self presentModalViewController:picker animated:YES];
[picker release];


}
- (IBAction)gotohomepage:(id)sender
{
[self dismissViewControllerAnimated:YES completion:nil];
}
- (BOOL)peoplePickerNavigationController:(ABPeoplePickerNavigationController *)peoplePicker shouldContinueAfterSelectingPerson:(ABRecordRef)person
{


ABAddressBookRef addressBook = ABAddressBookCreate();

int i;
NSString *strName = @"";
NSString* company = @"";
NSString *address = @"";
NSString *suburb = @"";
NSString *postalcode = @"";
NSString *state = @"";
NSString *country = @"";
NSString *mobile = @"";
NSString *phone = @"";
NSString *emailid = @"";


strName = (NSString *)ABRecordCopyCompositeName((ABRecordRef) person);
CFStringRef name = ABRecordCopyCompositeName((ABRecordRef) person);
company  = (NSString *)ABRecordCopyValue((ABRecordRef) person, kABPersonOrganizationProperty);

NSArray*  allPeople = (NSArray *)ABAddressBookCopyPeopleWithName(addressBook,name);
CFRelease(name);

for (i = 0; i < [allPeople count]; i++)
{
    ABRecordRef record = [allPeople objectAtIndex:i];

    ABMutableMultiValueRef multiValue = ABRecordCopyValue(record, kABPersonAddressProperty);
    for(CFIndex i=0; i<ABMultiValueGetCount(multiValue); i++)
    {
        NSString* HomeLabel = (NSString*)ABMultiValueCopyLabelAtIndex(multiValue, i);
        if([HomeLabel isEqualToString:@"_$!<Home>!$_"])
        {
            CFDictionaryRef dict = ABMultiValueCopyValueAtIndex(multiValue, i);
            address = [NSString stringWithFormat:@"%@", CFDictionaryGetValue(dict, kABPersonAddressStreetKey)];
            suburb = [NSString stringWithFormat:@"%@", CFDictionaryGetValue(dict, kABPersonAddressCityKey)];
            postalcode = [NSString stringWithFormat:@"%@", CFDictionaryGetValue(dict, kABPersonAddressZIPKey)];
            state = [NSString stringWithFormat:@"%@", CFDictionaryGetValue(dict, kABPersonAddressStateKey)];
            country = [NSString stringWithFormat:@"%@", CFDictionaryGetValue(dict, kABPersonAddressCountryKey)];

            CFRelease(dict);
        }
        CFRelease(HomeLabel);
    }
    CFRelease(multiValue);
}
CFRelease(allPeople);


ABMultiValueRef phones =(NSString*)ABRecordCopyValue(person, kABPersonPhoneProperty);
NSString* mobileLabel = nil;
for(CFIndex i = 0; i < ABMultiValueGetCount(phones); i++)
{
    mobileLabel = (NSString*)ABMultiValueCopyLabelAtIndex(phones, i);
    if([mobileLabel isEqualToString:(NSString *)kABPersonPhoneMobileLabel])
    {
        mobile = (NSString*)ABMultiValueCopyValueAtIndex(phones, i);
        NSLog(@"phone   %@",mobile);
    }
    else if ([mobileLabel isEqualToString:(NSString*)kABPersonPhoneIPhoneLabel])
    {
        phone = (NSString*)ABMultiValueCopyValueAtIndex(phones, i);
        NSLog(@"phone   %@",phone);

        CFRelease(mobileLabel);
        break ;
    }
    CFRelease(mobileLabel);

}
CFStringRef value, label;
ABMutableMultiValueRef multi = ABRecordCopyValue(person, kABPersonEmailProperty);
CFIndex count = ABMultiValueGetCount(multi);
if (count == 1)
{
    value = ABMultiValueCopyValueAtIndex(multi, 0);
    emailid = (NSString*) value;
    NSLog(@"self.emailID   %@",emailid);
    CFRelease(value);
}
else
{
    for (CFIndex i = 0; i < count; i++)
    {
        label = ABMultiValueCopyLabelAtIndex(multi, i);
        value = ABMultiValueCopyValueAtIndex(multi, i);

        // check for Work e-mail label
        if (CFStringCompare(label, kABWorkLabel, 0) == 0)
        {
            emailid = (NSString*) value;
            NSLog(@"self.emailID   %@",emailid);
        }
        else if(CFStringCompare(label, kABHomeLabel, 0) == 0)
        {
            emailid = (NSString*) value;
            NSLog(@"self.emailID   %@",emailid);
        }

        CFRelease(label);
        CFRelease(value);
    }
}
CFRelease(multi);    
CFRelease(phones);
CFRelease(addressBook);

[self dismissModalViewControllerAnimated:YES];

return NO;

}

推荐答案

在iOS6上苹果推出了新的隐私控制，用户可以通过每个应用控制联系人和日历的访问。因此，在代码方面，您需要添加一些方法来请求权限。在iOS5或更低版本中，我们始终可以调用

On iOS6, apple introduce new privacy control, user can control the accessment of contact and calender by each app. So, in the code side, you need to add some way to request the permission. In iOS5 or before, we can always call

ABAddressBookRef addressBook = ABAddressBookCreate();

获取地址簿没有任何问题，但是在iOS6中，如果没有权限，此调用只会返回空指针。这就是为什么我们需要更改获取ABAddressBookRef的方法。

to get the addressbook without any problem, but in iOS6, if you don't have permission, this call will just return empty pointer. That why we need to change the method to get ABAddressBookRef.

这种类型的错误通常在未授予访问地址簿权限的情况下出现。在这种情况下，请添加此内容代码的

This type of error generally appears when permission is not granted to access address book.In that case please add this piece of code

__block BOOL accessGranted = NO;
if (ABAddressBookRequestAccessWithCompletion != NULL) { // we're on iOS 6
    dispatch_semaphore_t sema = dispatch_semaphore_create(0);
    ABAddressBookRequestAccessWithCompletion(addressBook, ^(bool granted, CFErrorRef error) {
        accessGranted = granted;
        dispatch_semaphore_signal(sema);
    });
    dispatch_semaphore_wait(sema, DISPATCH_TIME_FOREVER);
    dispatch_release(sema);   
}
else { // we're on iOS 5 or older
    accessGranted = YES;
}

if (accessGranted) {
    // Do whatever you want here.
}

礼貌：- http://programmerjoe.blogspot.in/2012/10/ios6-permissions-contacts.html

如果这不能解决您的问题，请回信给我。

If this doesn't solves your problem ping me back..

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