如何在ruby中解码Rijndael（在VB.net中编码） [英] How to decode Rijndael in ruby (encoded in VB.net)

问题描述

我正在使用Rinjael在VB.NET中进行编码，并且需要在Ruby中进行解码。我的VB.NET加密类如下：

I am using Rinjael to encode in VB.NET and need to decode in Ruby. My VB.NET encryption class looks like this:

Private Class Encryptor
        Private symmetricKey As System.Security.Cryptography.RijndaelManaged
        Private iVector As Byte()
        Private Key As Byte()
        Public Function encrypt(ByVal data As String) As String
            Try
                Dim plainTextBytes As Byte() = System.Text.Encoding.ASCII.GetBytes(data)
                Dim encryptor As System.Security.Cryptography.ICryptoTransform = symmetricKey.CreateEncryptor(Key, iVector)
                Dim memoryStream As New System.IO.MemoryStream
                Dim cryptoStream As System.Security.Cryptography.CryptoStream = New System.Security.Cryptography.CryptoStream(memoryStream, encryptor, System.Security.Cryptography.CryptoStreamMode.Write)
                cryptoStream.Write(plainTextBytes, 0, plainTextBytes.Length)
                cryptoStream.FlushFinalBlock()
                Dim cipherTextBytes As Byte() = memoryStream.ToArray()
                memoryStream.Close()
                cryptoStream.Close()
                Return Convert.ToBase64String(cipherTextBytes)
            Catch
                Return ""
            End Try
        End Function
        Public Function decrypt(ByVal data As String) As String
            Try
                Dim crypted As Byte() = Convert.FromBase64String(data)
                Dim decryptor As System.Security.Cryptography.ICryptoTransform = symmetricKey.CreateDecryptor(Key, iVector)
                Dim memoryStream As New System.IO.MemoryStream(crypted)
                Dim cryptoStream As System.Security.Cryptography.CryptoStream = New System.Security.Cryptography.CryptoStream(memoryStream, decryptor, System.Security.Cryptography.CryptoStreamMode.Read)
                Dim plain(crypted.Length) As Byte
                Dim count As Integer = cryptoStream.Read(plain, 0, plain.Length)
                memoryStream.Close()
                cryptoStream.Close()
                Return System.Text.Encoding.UTF8.GetString(plain, 0, count)
            Catch
                Return ""
            End Try
        End Function

        Public Sub New(ByVal clientkey As String)
            iVector = System.Text.Encoding.ASCII.GetBytes("1234567890123456")
            Key = System.Text.Encoding.ASCII.GetBytes(clientkey)
            symmetricKey = New System.Security.Cryptography.RijndaelManaged
            symmetricKey.Mode = System.Security.Cryptography.CipherMode.CBC
        End Sub
    End Class

这可以正常工作，我能够使用AES / CBC / PKCS5Padding在Java中解密。现在，我的密码和iv为16个字符长（16 * 16bit = 256）。当我尝试在Ruby中解密时，它抱怨我的密码太短了……我认为它使用的是8位字符。我使用此类在ruby中进行解密：

this works ok and I am able to decrypt in java using the AES/CBC/PKCS5Padding. Now, my password and iv are 16 characters long (16*16bit = 256). When I try to decrypt in Ruby, it complains that my password is to short... I assume that it is using 8bit chars. I use this class for decryption in ruby:

    require 'openssl'

module Crypt
  # Decrypts a block of data (encrypted_data) given an encryption key
  # and an initialization vector (iv).  Keys, iv's, and the data 
  # returned are all binary strings.  Cipher_type should be
  # "AES-256-CBC", "AES-256-ECB", or any of the cipher types
  # supported by OpenSSL.  Pass nil for the iv if the encryption type
  # doesn't use iv's (like ECB).
  #:return: => String
  #:arg: encrypted_data => String 
  #:arg: key => String
  #:arg: iv => String
  #:arg: cipher_type => String
  def Crypt.decrypt(encrypted_data, key, iv, cipher_type)
    aes = OpenSSL::Cipher::Cipher.new(cipher_type)
    aes.decrypt
    aes.key = key
    aes.iv = iv if iv != nil
    aes.update(encrypted_data) + aes.final  
  end

  # Encrypts a block of data given an encryption key and an 
  # initialization vector (iv).  Keys, iv's, and the data returned 
  # are all binary strings.  Cipher_type should be "AES-256-CBC",
  # "AES-256-ECB", or any of the cipher types supported by OpenSSL.  
  # Pass nil for the iv if the encryption type doesn't use iv's (like
  # ECB).
  #:return: => String
  #:arg: data => String 
  #:arg: key => String
  #:arg: iv => String
  #:arg: cipher_type => String  
  def Crypt.encrypt(data, key, iv, cipher_type)
    aes = OpenSSL::Cipher::Cipher.new(cipher_type)
    aes.encrypt
    aes.key = key
    aes.iv = iv if iv != nil
    aes.update(data) + aes.final      
  end
end

现在。通过尝试使用Crypt.decrypt（data，key，iv， AES-CBC-256）进行解密，我可以确定必须对我的data，key，iv进行初步的字符串/字节转换才能正常工作。

Now. By trying to decrypt using Crypt.decrypt(data,key,iv, "AES-CBC-256") i am certain that preliminary string/byte transformations have to be done on my data,key,iv to work correctly.

如何使用key = passwordpassword和iv = 1234567890123456来调用Crypt.decrypt？
我需要对数据进行base64解码吗？

How shall I call Crypt.decrypt using key = "passwordpassword" and iv="1234567890123456"? Do I need to base64 decode my data?

这是我的解密调用，似乎没有用（尝试使用零填充）：

Here's my decryption call, which doesn't seem to work (trying padding with zeroes):

   text = Base64.decode64(text)
   pass = Digest::SHA1.hexdigest("#{@pass}0000000000000000").unpack('a2'*32).map{|x| x.hex}.pack('c'*32)
   iv = Digest::SHA1.hexdigest("12345678901234560000000000000000").unpack('a2'*32).map{|x| x.hex}.pack('c'*32)
   return Crypt.decrypt(text,pass,iv,"AES-256-CBC")

推荐答案

解决方案。它是一种128位加密（错误地认为.NET管理的默认值为256）。因此，此代码有效（注意 AES-128-CBC）：

Solution. It was a 128bit encryption (wrongly thinking that the default in .NET managed was 256). Hence, this code works (notice "AES-128-CBC"):

   text = Base64.decode64(text)
   pass = "passwordpassword"
   iv = "1234567890123456"
   return Crypt.decrypt(text,pass,iv,"AES-128-CBC")

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