选择仅按列分组，而不是合计 [英] Select grouped by column only, not the aggregate

问题描述

在涉及聚合的MySql select语句中，是否可以仅选择按列分组而没有聚合的分组？

In a MySql select statement involving aggregation, is it possible to select just the grouped by column without the aggregate?

基本上，我想根据基于总计的条件在子查询中选择ID，在这种情况下，向客户的总付款额：

Basically I want to select IDs in subquery according to a criteria based on an aggregate, in this case the total payments to a client:

select idclient, business_name from client where idclient in
(
  select idclient, sum(amount) as total 
  from payment 
  group by idclient
  having total > 100
)

...但这失败并显示错误 Operand应该包含1列，因为子查询同时选择了ID（我想要的）和总计（我不需要的）。是否可以通过任何方式从子查询结果中排除总数？

... but this fails with error Operand should contain 1 column(s) because the subquery selects both the id (which I want) and the total (which I don't). Can I exclude total from the subquery result in any way?

编辑：如果可能，我宁愿避免使用一个联接-where子句将自己传递给另一个现有函数。

if possible I would prefer to avoid using a join - the where clause is being passed onto another existing function on its own.

很抱歉，这很抱歉-我确实做了搜索。我在大量的SQL汇总问题中找不到确切的答案。

推荐答案

您的查询应该像此：

select idclient, business_name from client where idclient in
(
  select idclient 
  from payment 
  group by idclient
  having sum(amount) > 100
)

您需要将聚合函数放在having子句中，并且在子查询中，您需要选择与where子句中相同的列数。

You need to put aggregate function in having clause and in sub query you need to select # of columns same as in your where clause.

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