复制Excel SUMIFS公式 [英] Replicating an Excel SUMIFS formula

问题描述

我需要为Excel中的SUMIFS函数复制（或至少找到替代解决方案）。

I need to replicate - or at least find an alternative solution - for a SUMIFS function I have in Excel.

我有一个事务数据库：

SegNbr  Index   Revenue SUMIF
A         1       10     30
A         1       20     30
A         2       30     100
A         2       40     100
B         1       50     110
B         1       60     110
B         3       70     260
B         3       80     260

，我需要创建另一个列，该列将等于或小于该行中Index的所有索引按SegmentNumber的总和计入收入。这是一种扭曲的滚动收入，因为每个SegmentNumber / Index键都相同。这是这个公式：

and I need to create another column that sums the Revenue, by SegmentNumber, for all indexes that are equal or less the Index in that row. It is a distorted rolling revenue as it will be the same for each SegmentNumber/Index key. This is the formula is this one:

=SUMIFS([Revenue],[SegNbr],[@SegNbr],[Index],"<="&[@Index])

推荐答案

假设您有此示例数据。

dd<-read.table(text="SegNbr  Index   Revenue
A         1       10
A         1       20
A         2       30
A         2       40
B         1       50
B         1       60
B         3       70
B         3       80", header=T)

现在，如果我们确定数据的排序依据段和索引，我们可以这样做

Now if we make sure the data is ordered by segment and index, we can do

dd<-dd[order(dd$SegNbr, dd$Index), ]  #sort data
dd$OUT<-with(dd, 
    ave(
        ave(Revenue, SegNbr, FUN=cumsum),  #get running sum per seg
        interaction(SegNbr, Index, drop=T), 
    FUN=max, na.rm=T) #find largest sum per index per seg
)
dd

这给出了

  SegNbr Index Revenue OUT
1      A     1      10  30
2      A     1      20  30
3      A     2      30 100
4      A     2      40 100
5      B     1      50 110
6      B     1      60 110
7      B     3      70 260
8      B     3      80 260

根据需要。

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