$（TZ = MSZ + 24 date +“％d％m％Y”）在夏令时期间无法正常工作？ [英] $(TZ=MSZ+24 date +"%d%m%Y") not working as expected during daylight savings?

问题描述

我有一个脚本，该脚本利用 $（TZ = MSZ + 24 date +％d％m％Y）来获取昨天的BASH日期（AIX系统）。到目前为止，它已经完美地工作了5个月，直到昨晚它无法正常工作为止。通常，它在服务器时间上午01:00运行，但是昨晚发生了一些奇怪的事情，并且它不起作用的唯一原因是因为 $（TZ = MSZ + 24 date +％d％ m％Y）。

I have a script that makes use of $(TZ=MSZ+24 date +"%d%m%Y")to get yesterday's date in BASH (AIX system). So far it's worked flawlessly for 5 months, until last night, when it didn't worked properly. Usually it runs at 01:00 AM server time, but last night something strange happened, and the only reason it wouldn't have worked is because of $(TZ=MSZ+24 date +"%d%m%Y").

所以，我的问题是，如果星期六晚上时钟前进1个小时，会影响 $（TZ = MSZ + 24 date + ％d％m％Y），所以当它在星期日运行时，它会给出奇怪的结果吗？

So, my question is, if Saturday night the clock went forward 1 hour, could it influence $(TZ=MSZ+24 date +"%d%m%Y") so when it ran on Sunday, it would have given a strange result ?

谢谢

推荐答案

由于夏时制，24几小时前可以是今天或前天。如果要在不使用GNU日期的情况下更改脚本，请使用以下技巧：

Due to the daylight saving time, 24 hours ago can be today or the day before yesterday. When you want to change your script without using the GNU-date, use the following trick:

您确定昨天是20或30小时前。哪一个？好吧，最近的不是今天。

You are sure that yesterday is 20 or 30 hours ago. Which one? Well, the most recent one that is not today.

echo "$(TZ=MSZ+30 date +"%d%m%Y")
$(TZ=MSZ+20 date +"%d%m%Y")" | grep -v "$(date +"%d%m%Y")" | tail -1

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