您可以在C＃中将findcontrol与Ajax手风琴一起使用吗？ [英] Can you use findcontrol with an Ajax Accordion in c#?

问题描述

这伴随着我所问的另一个问题，我的主页上有一个下拉列表，该下拉列表在更改时导致回发，并且在该索引更改方法中，我试图找到我的Ajax手风琴来查看选定的索引

This goes along with another question that I have asked, I have a drop down list on my master page that causes postback when changed and in that index changed method I am trying to find my ajax accordion to look at the selected index of it

protected void ddlSelectedCustomer_SelectedIndexChanged(object sender, EventArgs e)
{
    CustomerSelected();

    Response.AppendHeader("Refresh", "0;URL=storefront.aspx");

    ViewState["SelectedAccordionIndex"] = (AjaxControlToolkit.Accordion)FindControl("MyAccordion").SelectedIndex;
}

我得到的错误

对象引用未设置为对象的实例。

Object reference not set to an instance of an object.

推荐答案

问题是FindControl返回对象。将其转换为手风琴，然后重试： ViewState [ SelectedAccordionIndex] =（（（Accordion）FindControl（ MyAccordion））。SelectedIndex;

the problem is FindControl returns an Object. Cast it to an accordion and try again: ViewState["SelectedAccordionIndex"] = ((Accordion)FindControl("MyAccordion")).SelectedIndex;

如果这不是为什么，您可能需要更深入地研究，例如（（（Accordion）this.FindControl（<您的手风琴所在的内容占位符的ID）>）。FindControl（ MyAccordion））。SelectedIndex;

If this doesn't why you may need to drill deeper, e.g. ((Accordion)this.FindControl(<the id of your content placeholder your accordion is in>).FindControl("MyAccordion")).SelectedIndex;

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