在列中找到值 [英] Locate value in column
本文介绍了在列中找到值的处理方法,对大家解决问题具有一定的参考价值,需要的朋友们下面随着小编来一起学习吧!
问题描述
我正在将Elastic Load Balancing Access日志传递给Athena,我想获取位于URL列中的值。下面的代码适用于mySQL,但是Athena使用SQL可以从下面的方法中获取县的价值吗?
I am passing Elastic Load Balancing Access logs to Athena and I want to get a value that is located in the URL column. The below works for mySQL but Athena uses SQL is there a way I can grab the value of county from the below?
create table elb_logs(row varchar(100), url varchar(100));
insert into elb_logs values("Row1", "Lauguage=English&Country=USA&Gender=Male");
insert into elb_logs values("Row2", "Gender=Female&Language=French&Country=");
insert into elb_logs values("Row3", "Country=Canada&Gender=&Language=English");
insert into elb_logs values("Row4", "Gender=&Language=English");
SELECT `row`, IF(LOCATE('Country=', url)>0,
COALESCE(
NULLIF(SUBSTRING_INDEX(SUBSTRING_INDEX(url, 'Country=', -1), '&', 1), ''),
'Blank string is not valid!'),
'Missing Country!') AS ColumnB
FROM `elb_logs`
+------+----------------------------+
| row | ColumnB |
+------+----------------------------+
| Row1 | USA |
| Row2 | Blank string is not valid! |
| Row3 | Canada |
| Row4 | Missing Country! |
+------+----------------------------+
推荐答案
SPLIT_PART
函数似乎在这里可用:
The SPLIT_PART
function would seem to be usable here:
SELECT
row,
CASE WHEN POSITION('Country=' IN url) > 0
THEN SPLIT_PART(SPLIT_PART(url, 'Country=', 2), '&', 1)
ELSE 'Missing Country!' END AS ColumnB
FROM elb_log;
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