PHP垂直字母使用FOR循环 [英] PHP Vertical Alphabet Using FOR Cycle
问题描述
我正在尝试使用PHP编写脚本，该脚本将生成一个带有垂直字母的表格。它将简单地将字母从A回显到Z，当涉及到Z时，它将重置并再次从A开始。我有一个问题，因为我只能重复两次，然后所有单元格中都有一些不需要的信号。我正在使用其ASCII html代码回显该字母，其中A符号为&＃65，Z符号为&＃90。
I'm trying to do a script in PHP which will generate a table with vertical alphabet in it. It will simply echo letters from A to Z and when it comes to Z, it will reset and begin from A again. I have a problem with this because I only can repeat this twice, then all cells have some unwanted signs in them. I'm echo-ing the letter using their ASCII html codes, where the A sign is A and the Z sign is Z.
<!DOCTYPE html>
<html>
<head>
<meta content="text/html; charset=utf-8" http-equiv="Content-Type">
<title>Vertical alphabet</title>
</head>
<body>
<form method="post">
<input type="number" placeholder="COLUMNS" name="cols" />
<input type="number" placeholder="ROWS" name="rows" />
<input type="submit" value="Create table" /><br><br>
</form>
<?php
if(isset($_POST['rows']) && isset($_POST['cols'])) {
$col = $_POST['cols'];
$row = $_POST['rows'];
echo ("<table rules='all'>");
for($i = 1; $i<$row+1; $i++) {
echo ("<tr>");
for($c = 0; $c<$col; $c++) {
$letter_id = 65;
$number = ($i + ($c*$row)-1);
$letter = $number + $letter_id;
if($letter > 90) {
$number = $number - 26;
$letter = $letter - 26;
echo ("<td>". "&#" . $letter. "</td>");
} else {
echo ("<td>". "&#" . $letter. "</td>");
}
}
echo ("</tr>");
}
echo ("</table>");
}
?>
</body>
</html>
推荐答案
不确定您要使用 $ number 变量，但这就是这里的问题
Not sure what you're trying to with the $number variable, but that's the issue here
$number = 0;
echo ("<table rules='all'>");
for($i = 1; $i<=$row; $i++) {
echo ("<tr>");
for($c = 0; $c<$col; $c++) {
$letter_id = 65;
$number = $i + ($c*$row);
$letter = $number + $letter_id;
while($letter > 90) {
$letter = $letter - 26;
}
echo ("<td>". "&#" . $letter. "</td>");
}
echo ("</tr>");
}
echo ("</table>");
已更新：
现在垂直，尝试这个...
Now vertical, try this...
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