我总是看到“ E ActivityManager:从系统发送不受保护的广播”在android 7中是什么意思? [英] I always see "E ActivityManager: Sending non-protected broadcast from system" in android 7. What does this mean?
问题描述
我正在尝试使用以下功能从非系统应用发送意图。
I am trying to send an intent from a non system app using the following function.
public static void sendIntent() {
if (null != _context) {
Intent intent = new Intent("com.test.testApp.testIntent");
intent.setPackage(_context.getPackageName());
_context.sendBroadcast(intent);
}
}
但是我总是看到来自ActivityManager的错误消息如下。相同的Intent Broadcast(app)在Andorid 6.0中工作正常,但在android 7.1.1中引发错误。我需要为android 7.1.1更改任何内容吗?
But I always see there is an error message from ActivityManager as below. The same intent broadcasting(app) works fine in andorid 6.0 but throws an error in android 7.1.1. I am required to change anything for android 7.1.1?
4-10 15:06:34.423 1615 2921 E ActivityManager:发送不受保护的广播com.test.testApp来自系统2886的.testIntent:com.test.testApp / u0a117 pkg com.test.testApp
4-10 15:06:34.423 1615 2921 E ActivityManager: Sending non-protected broadcast com.test.testApp.testIntent from system 2886:com.test.testApp/u0a117 pkg com.test.testApp
在ListFragment中,我按以下方式注册接收者:
In a ListFragment I register the receiver as follows:
@Override
public void onStart() {
super.onStart();
getActivity().registerReceiver((receiver),
new IntentFilter(com.test.testApp.testIntent));
TextView textDownload = (TextView) getActivity().findViewById(R.id.output);
textDownload.setVisibility(android.view.View.INVISIBLE);
}
推荐答案
这可能会有帮助,
如果您在AndroidManifest.xml中声明了 android:sharedUserId = android.uid.system,则声明受保护的广播。
If you have in your AndroidManifest.xml declared "android:sharedUserId="android.uid.system", then declare the protected broadcast.
参考资料: https://stackoverflow.com/a/50240471
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