Python正则表达式转义字符 [英] python regex escape characters

问题描述

我们有：

>>> str
'exit\r\ndrwxr-xr-x    2 root     root            0 Jan  1  2000 
\x1b[1;34mbin\x1b[0m\r\ndrwxr-xr-x    3 root     root           
0 Jan  1  2000 \x1b[1;34mlib\x1b[0m\r\ndrwxr-xr-x   10 root     
root            0 Jan  1  1970 \x1b[1;34mlocal\x1b[0m\r\ndrwxr-xr-x    
2 root     root            0 Jan  1  2000 \x1b[1;34msbin\x1b[0m\r\ndrwxr-xr-x    
5 root     root            0 Jan  1  2000 \x1b[1;34mshare\x1b[0m\r\n# exit\r\n'

>>> print str
exit
drwxr-xr-x    2 root     root            0 Jan  1  2000 bin
drwxr-xr-x    3 root     root            0 Jan  1  2000 lib
drwxr-xr-x   10 root     root            0 Jan  1  1970 local
drwxr-xr-x    2 root     root            0 Jan  1  2000 sbin
drwxr-xr-x    5 root     root            0 Jan  1  2000 share
# exit

我想使用regexp摆脱所有的'\xblah [0m废话。我已经尝试过

I want to get rid of all the '\xblah[0m' nonsense using regexp. I've tried

re.sub(str, r'(\x.*m)', '')

但这并没有解决问题。有想法吗？

But that hasn't done the trick. Any ideas?

推荐答案

您遇到了一些问题：

• 您正在以错误的顺序将参数传递给re.sub。应该是：

• You're passing arguments to re.sub in the wrong order wrong. It should be:

re.sub（regexp_pattern，替换，source_string）

re.sub(regexp_pattern, replacement, source_string)

字符串不不包含 \x。 \x1b是转义字符，并且是单个字符。

The string doesn't contain "\x". That "\x1b" is the escape character, and it's a single character.

正如interjay所指出的，您想要。*？而不是。*，因为否则它将匹配从第一个转义到最后一个 m的所有内容。

As interjay pointed out, you want ".*?" rather than ".*", because otherwise it will match everything from the first escape through the last "m".

对re.sub的正确调用是：

The correct call to re.sub is:

print re.sub('\x1b.*?m', '', s)

或者，您可以使用：

print re.sub('\x1b[^m]*m', '', s)

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