斯威夫特2 arch4random [英] Swift 2 arch4random

问题描述

在我的应用程序中，我使用类似的方式在标签上获取随机文本，但在我的主要 let randomNumber 代码中，xCode中有300多种情况，

In my application, I use something like this to get random text on my label, except in my main let randomNumbercode, in xCode, it has over 300 cases, to much to paste in here.:

let randomNumber = Int(arc4random_uniform(23))
var textLabel = "" as NSString
switch (randomNumber){
case 1:
    textLabel = "Kim."
    break
case 2:
    textLabel = "Phil."
    break
case 3:
    textLabel = "Tom"
    break
case 4:
    textLabel = "Jeff"
    break
default:
    textLabel = "Austin"
}
self.randomLabel.text = textLabel as String

但是问题是，有时它会在标签上显示相同的文本5-6次，而其他情况甚至没有使用，因为它是随机选择的。因此，我该如何随机选择，但是如果案例示例案例1已经显示，它将不会再次显示，直到显示了所有其他案例。

But the problem is, that sometimes it shows the same text on the label 5-6 times, and other cases is not even used yet, because it choose randomly. So how can I choose randomly, but if case example case 1 is already shown, it wont show up again, until all other cases has been shown.

推荐答案

具有一个名称数组，而不是一个巨大的切换用例：

Have an array of Names instead of a gigantic switch case:

var names = ["Kim.", "Phil.", "Tom", "Jeff", "Austin"] // and all your remaining names
let originalNames = names

func getRandomName() -> String {
    if (names.count == 0) {
        names = originalNames
    }
    let randomNumber = Int(arc4random_uniform(UInt32(names.count)))
    return names.removeAtIndex(randomNumber)
}

这可以确保每个名称在开始之前就被打印从头开始。示例输出为：

This ensures every name gets printed before starting from the beginning again. The sample output is:

Tom，Kim。，Austin，Phil。，Jeff

Tom, Kim., Austin, Phil., Jeff

，然后重新开始

奥斯汀，杰夫，菲尔。 ...

Austin, Jeff, Phil. ...

最后在需要的地方放置以下内容：

Finally put something like the following wherever it fits your need:

self.randomLabel.text = getRandomName()

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