如何在Flask应用程序中创建动态子域 [英] How to create dynamic subdomains in a Flask application
问题描述
我正在尝试在Flask应用程序中设置变量路由处理,例如此答案中所述: Web应用程序中的动态子域处理(Flask)
I am trying to setup variable route handling in a Flask application such as described in this answer: Dynamic Subdomain Handling in a Web App (Flask)
但是,我希望能够在被捕获之前识别出某些子域通过变量路由,这样我就可以使用flask-restful api扩展名(使用RESTful路由)。
However, I want to be able to recognize certain subdomains BEFORE they are caught by the variable route so I can use the flask-restful api extension (Routing with RESTful).
例如,我尝试了以下操作:
For example, I have tried the following:
@app.route('/', subdomain="<user>", defaults={'path':''})
@app.route('/<path:path>', subdomain="<user>")
def user_profile(user,path):
pass
class Api(restful.Resource):
def get(self):
#Do Api things.
api.add_resource(Api, '/v1', subdomain="api")
当我对此进行测试时,所有URL都进入变量路由处理程序并调用 user_prof()
。我尝试将api路由放在首位,将标准 @ app.route
规则放在第二位,反之亦然,但是没有任何变化。
When I test this, all of URLs go to the variable route handler and call user_prof()
. I tried putting the api route first and the standard @app.route
rule second and vice versa but there was no change.
我是否还缺少其他参数或需要深入研究Flask才能做到这一点?
Am I missing some other parameter or need to go deeper in Flask to make this happen?
我要匹配的网址格式如下:
The URL patterns I am trying to match are like this:
user1.mysite.com -> handled by user_profile()
user2.mysite.com -> handled by user_profile()
any_future_string.mysite.com -> handled by user_profile()
api.mysite.com/v1 -> handled by Api class
处理其他情况包括:
www.mysite.com -> handled by index_display()
mysite.com -> handled by index_display()
处理
推荐答案
@app.before_request
def before_request():
if 'api' == request.host[:-len(app.config['SERVER_NAME'])].rstrip('.'):
redirect(url_for('api'))
@app.route('/', defaults={'path': ''}, subdomain='api')
@app.route('/<path:path>', subdomain='api')
def api(path):
return "hello"
这应该有效。如果需要或可以由您的API类处理,请将您的api版本添加到路径中。
This should work. Add your api version to the path if needed or that could be processed by your API class.
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