耶索德全包路线 [英] Yesod catchall route

问题描述

我正在构建一个由两部分组成的yesod应用。其余的api（yesod）和客户端的（angularjs）。

I'm building a yesod app which consists of two parts. The rest api (yesod) and the client side (angularjs).

除了作为REST api之外，yesod还将初始的html发送给客户端以启动angularjs。我有这样的工作：

Besides being a rest api, yesod also send the initial html to the client to start up angularjs. I have it working like this:

配置/路由：

/user GET
/someOtherEntity GET POST
/ HomeR GET --route to send the html

$ b $的路由b

Handler / Home.hs

Handler/Home.hs

getHomeR :: Handler Html                                                                            
getHomeR = sendFile typeHtml "frontend/build/index.html" 

只要第一个网址是www.mydomain.com/， ，但是当我访问www.mydomain / some-angular / route时，我从yesod收到了404。

As long as the first url is www.mydomain.com/ this works fine, but when I go to www.mydomain/some-angular/route I get a 404 from yesod.

我已经尝试过：

/#Text HomeR GET

这对于/ my-angular-route正常工作，但在/ my-angular-route / param上中断。我可以添加/＃Text /＃Text，但是肯定有一种更清洁的方式来处理此问题。

This works fine for /my-angular-route, but breaks on /my-angular-route/param. I could add /#Text/#Text I suppose, but surely there's a cleaner way of handling this.

我如何实现某种形式的全程捕获？因此，只要不是与路由匹配的网址，都应该调用getHomeR。

How can I implement some sort of catch all route? So whenever it's not an url which matches a route, it should just call getHomeR.

推荐答案

您可以使用多段路由，并且可能需要关闭重叠检查。看起来像这样：

You can use multi-piece routes, and will likely need overlap checking turned off. This would look like:

!/*Texts HomeR GET

有关更多信息，请参见路由章节。

For more information, see the routing chapter of the Yesod book.

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