如何在应用程序中创建深层链接？ [英] How to create a deep link in app?

问题描述

我正在应用程序中工作。需要创建一个深层链接。用户可以共享特定项目，并且可以从单击链接打开直接页面。我按照在此处输入链接描述

I am working in app. There need to create a deep link. User can able to share particular item and user can open direct page from click link. I follow enter link description here

 <intent-filter >
          <!--  android:autoVerify="true"-->

       <action android:name="android.intent.action.VIEW" />
       <category android:name="android.intent.category.DEFAULT" />
       <category android:name="android.intent.category.BROWSABLE" />

            <data android:scheme="https"
                android:host="www.jobzminer.com"
                android:pathPrefix="/appplay" />

            <data android:scheme="jobzminer"
                android:host="appplay" />
   </intent-filter>

但是当我将链接放入浏览器时，它将无法正常工作。

but when i put link into browser then its not working.

推荐答案

如评论中所述，将您的网址更新为： https://www.jobzminer.com/appplay 。另外，将浏览器清除为默认应用。

As mentioned in the comments, to update your url to: https://www.jobzminer.com/appplay. Also clear your browser as a default app.

要传递参数，可以使用查询参数。像这样更改您的网址： https://www.jobzminer.com/appplay?param1=hello&param2=world

To pass parameters, you could use query parameters. Change your url like this: https://www.jobzminer.com/appplay?param1=hello&param2=world

然后参加您的活动。这样做：

Then in your activity. Do this:

Intent intent = getIntent();
Uri data = intent.getData();
String param1 = data.getQueryParameter("param1");
String param2 = data.getQueryParameter("param2");

您还可以看到我的答案此处。

You can also see my answer here.

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