Java中最高精度的测试编号 [英] Test Number For Maximum Precision In Java

问题描述

我想测试双精度的最大精度为3或更小.用Java做到这一点的最佳方法是什么?

I would like to test a double for a maximum percision of 3 or less. What is the best way to do this in Java?

20.44567567 <- Fail
20.444 <- Pass
20.1 <- Pass
20 <- Pass

推荐答案

1)不要使用double.浮点逻辑充其量是近似的.改为使用BigDecimal.

1) Do not use double. Floating point logic is approximated at best. Use BigDecimal instead.

2)我认为BigDecimal已经有一种设置精度的方法.如果不是，则乘以1000并截断.进行操作，获取一个新的数字，然后与原始数字进行比较.如果不同，则失败.

2) I think BigDecimal already has a way of setting a precision. If not, just multiply by 1000 and trunc. Do the operation, get a new number, and compare to the original one. If it is different, fail.

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