长双倍输出的精度不正确.可能是什么问题? [英] The precision of the long double output is not correct. What might be wrong?
问题描述
我有一个long double
常量,我将其设置为const或not-const.它比我的测试工作站上的long double
的精度(19位)长(40位).
I have a long double
constant that I am setting either as const or not-const. It is longer (40 digits) than the precision of a long double
on my test workstation (19 digits).
当我打印出来时,它不再以19位精度显示,而是以16位精度显示.
When I print it out, it no longer is displayed at 19 digits of precision, but at 16.
这是我正在测试的代码:
Here is the code I am testing:
#include <iostream>
#include <iomanip>
#include <limits>
#include <cstdio>
int main ()
{
const long double constLog2 = 0.6931471805599453094172321214581765680755;
long double log2 = 0.6931471805599453094172321214581765680755;
std::cout << std::numeric_limits<long double>::digits10 + 1 << std::endl;
std::cout << "const via cout: " << std::setprecision(19) << constLog2 << std::endl;
std::cout << "non-const via cout: " << std::setprecision(19) << log2 << std::endl;
std::fprintf(stdout, "const via printf: %.19Lf\n", constLog2);
std::fprintf(stdout, "non-const via printf: %.19Lf\n", log2);
return 0;
}
编译:
$ g++ -Wall precisionTest.cpp
输出:
$ ./a.out
19
const via cout: 0.6931471805599452862
non-const via cout: 0.6931471805599452862
const via printf: 0.6931471805599452862
non-const via printf: 0.6931471805599452862
我希望0.6931471805599453094
,但得到0.6931471805599452862
.
将19位精度降低到16位是有原因的吗?
Is there a reason that the 19 digits of precision are cut to 16 digits?
这是我的环境:
$ gcc --version
i686-apple-darwin9-g++-4.0.1 (GCC) 4.0.1 (Apple Inc. build 5490)
我在其他版本的gcc上遇到了同样的问题,例如:
I am seeing the same problem with other versions of gcc, e.g.:
$ gcc --version
g++ (GCC) 3.4.6 20060404 (Red Hat 3.4.6-10)
我可以查看NTL或其他库,但是我很好奇是什么原因造成的.感谢您的见识.
I can look into NTL or other libraries but I'm curious what is causing this. Thanks for your insight.
推荐答案
我得到以下输出:
19
const via cout: 0.6931471805599453094
non-const via cout: 0.6931471805599453094
const via printf: 0.6931471805599453094
non-const via printf: 0.6931471805599453094
但是我使用的是长双字面量而不是双字面量:
But i'm using long double literals instead of double literals:
const long double constLog2 = 0.6931471805599453094172321214581765680755L;
long double log2 = 0.6931471805599453094172321214581765680755L;
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