从char数组中删除重复项的Java方法 [英] Java Method for removing duplicates from char array

问题描述

我有一个由用户(arrayInput[])填充的字符数组，其中包含一些字符，例如{b，d，a，b，f，a，g，a，a，f}，我需要创建一个方法，该方法返回仅具有字符的第一个匹配项但按输入顺序的新char数组.该书还说:解决此问题的一种方法是创建一个布尔数组来跟踪要维护的字符！"，但我无法想象布尔数组应如何与其他数组一起工作.

I have a char array filled by the user (arrayInput[]) with some characters, like {b, d, a, b, f, a, g, a, a, f}, and I need to create a method which returns a new char array with only the first occurrence of the character, but in the order of input. The book also says "A way to solve this problem is to create a boolean array to keep track of the characters to mantain!", but I can't imagine how the boolean array should work with the other arrays.

主要问题是，如果arrayInput包含一个特定字符，甚至是多少次，我都可以保存在一个布尔数组中，但是只能将一个很长的分支if-else创建为for，例如

The main problem is that I can save in a boolean array if arrayInput contains a specific character, and even how many times, but only creating a very long ramified if-else into a for, like

    if ((arrayOutput[i] == 'A') && (arrayControl[0] = false)) {
        arrayControl[0] = true;  }

其中，arrayOutput是我要从该方法返回的数组，arrayControl[0]是我在该方法中创建的布尔数组中的'A'值. A = 0，B = 1，... Z = 25，a = 26，b = 27，... 51 = z.对于每个单个字符(大写和小写)，我都在数组中创建了一个位置，因此可以检查所有内容，但是现在我无法再进行任何操作了.我不知道如何将字符保存在arrayOutput上，如何检查字符是否已经在arrayOutput上，以及是否已经存在，数组会传递该特定字符并转到下一个字符.

where arrayOutput is the array I want to return from the method, arrayControl[0] is the value of 'A' in my boolean array I created into the method. A = 0, B = 1, ... Z = 25, a = 26, b = 27, ... 51 = z. For every single character, uppercase and lowercase, I created a place into the array, so I could check everything, but now I can't go any further. I don't know how to save the characters on arrayOutput, how to check if a character is already on arrayOutput and if it's already there, the array passes that specific character and go to the next one.

也请记住我是新手，所以我对Java知之甚少.请尽自己所能解释.提前致谢！

Also please remember I'm a newbie, so I know very little about Java. Please explain yourself the best you can. Thanks in advance!

推荐答案

这可能有效:

public static void main(String[] args) {
    Main main = new Main();
    char[] array = {'e','a','b','a','c','d','b','d','c','e'};
    main.getCharArray(array);
}

private char[] getCharArray(char[] array) {
    String _array = "";
    for(int i = 0; i < array.length; i++) {
        if(_array.indexOf(array[i]) == -1) // check if a char already exist, if not exist then return -1
            _array = _array+array[i];      // add new char
    }
    return _array.toCharArray();
}

输出:

eabcd

Output:

eabcd

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