固定精度且无句点的十进制自定义格式字符串 [英] decimal custom format string with fixed precision and no period
问题描述
我遇到了一种情况,我认为您无法使用自定义格式字符串.
I've run into a situation which I think is beyond what you can do with custom format strings.
但是我写的代码太过粗糙了,我以为我还是会问.
But the code I've written is so gross I thought I would ask anyway.
我需要的是将小数点显示为6或7位数字的字符串,如下所示:
What I need is for a decimal to be displayed as either a 6 or 7 digit string, like so:
number = 12345.67M
(optional)
tenthousands thousands hundreds tens ones tenths hundredths
1 2 3 4 5 6 7
这是我为实现此目的而编写的代码:
Here's the code I've written to achieve this:
public static string ConvertDecimalToString(decimal easting, int length)
{
var formatString = "{0:0000.00}";
var numberAsString = string.Format(formatString, easting);
var removePeriod = numberAsString.Replace(".", "");
if (removePeriod.Length > length)
{
return removePeriod.Substring(removePeriod.Length - length, length);
}
else
{
return removePeriod.PadLeft(length, '0');
}
}
预期的输入和输出:
Expected inputs and outputs:
Input Output(6) Output(7)
912345.67M 234567 1234567
12345.67M 234567 1234567
1234.56M 123456 0123456
1234.5M 123450 0123450
1234M 123400 0123400
234M 023400 0023400
推荐答案
如果您想将小数12345.67
显示为1234567
(只需省略小数点),请使用以下技巧:
If you want a decimal 12345.67
displayed as 1234567
(just omit the decimal point) use this trick:
decimal number = 12345.67M;
string s = string.Format("{0:0000000}", number * 100.0);
或
string s = string.Format("{0:F0}", number * 100.0); // zero decimal places
士气:不要摆弄格式化产生的字符串,而是修改输入值,然后让格式化完成其工作.
Morale: Do not fiddle with a string produced from formatting, modify the input value instead and let the formatting do its job.
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