fpc的运行时错误201 [英] Runtime Error 201 at fpc
本文介绍了fpc的运行时错误201的处理方法,对大家解决问题具有一定的参考价值,需要的朋友们下面随着小编来一起学习吧!
问题描述
我一直在写关于猜数字的游戏,我必须将4位数字分解成数字并将数字放入数组中,但是该部分始终使用fpc给出运行时错误201,但是当我使用ideone.com时它给了我我想要的东西.我不知道.这可能是个错误吗?对不起我的英语.
i have been writing a game about guessing numbers and i have to seperate a 4 digit number into its digits and put digits into an array.However that section keeps giving me runtime error 201 using fpc.However when i use ideone.com it gives me what i want.I can't figure out.can it be a bug?Sorry for my English.
program game;
var
number : array [1..4] of integer;
z, i, j: integer;
number_4digit: integer;
begin
readln(number_4digit);
for i := 4 downto 1 do begin
j := i;
z := number_4digit;
while z > 10 do begin
z := z div 10;
end;
number[5-i] := z;
repeat
z := z * 10;
j := j - 1;
until j = 1;
number_4digit:= number_4digit - z;
write(number[5-i], ' ');
end;
end.
我解决了这个问题.感谢Marco van de Voort.
I solved the problem.Thanks for Marco van de Voort.
repeat
z := z * 10;
j := j - 1;
until j = 1;
我将本节更改为此.
while j > 1 do begin
z := z * 10;
j := j - 1;
end;
推荐答案
- 在for循环之后,J始终为1.
- 然后在重复循环中将其递减(至j = 0).
- 不等于1,因此它再次减小到-1直到-32768,然后翻转到32767
- 然后将32767转换为1.
总而言之,重复执行65536 +/- 1次.我从代码中不清楚J变量的含义.评论更多.
In summary the repeat is done 65536 +/-1 times. The meaning of the J variable is not clear to me from the code. Comment more.
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