在javascript中解压缩GVariant [英] unpacking GVariant in javascript

问题描述

我有一个数组存储为GSettings中类型为a(ss)的GVariant，我想在肉桂Applet中使用它.我可以使用以下代码成功检索值:

I have an array stored as a GVariant of type a(ss) in GSettings, that I want to use in a Cinnamon Applet. I can retrieve the value successfully using the following code:

let schema = schema_source.lookup(SCHEMA_NAME, false);
let settings = new Gio.Settings({ settings_schema: schema });
let my_value = settings.get_value('myvalue');

但是我不能打开它的包装.据我所知，我可能需要使用GVariantIter结构将其解压缩，但文档有限，而且我无法在gjs API中找到正确的接口(如果确实存在).有人知道怎么做吗?

but I can't unpack it. As far as I can see, I will probably need to unpack it using a GVariantIter structure, but the documentation is limited, and I can't find the correct interface in the gjs API (if, indeed, it exists). Does anyone know how to do it?

谢谢！

修改: 我的架构如下:

<key type="a(ss)" name="myvalue">
    <default>[]</default>
    <summary>an array of (string, string) tuples</summary>
    <description></description>
</key>

目前，我正在使用外部JSON文件存储设置，但这并不是100％令人满意的解决方案.我想我可以维护两个as类型的变量，并使它们保持对齐，但是必须有一种正确执行此操作的方法，对吗?

For the time being I'm using an external JSON file to store settings, but it's not a 100% satisfactory solution. I suppose I could maintain two as-type variables, and keep them aligned, but there must be a way to do this properly, right?

推荐答案

有点晚，但是my_value.unpack()绝对可以.

A bit late, but my_value.unpack() works absolutely fine.

my_value.deep_unpack()将递归解压缩数组及其元素.

my_value.deep_unpack() will recursively unpack the arrays and their elements.

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