无法使用HAPI TERSER解析HL7中的多个IN1段 [英] Unable to Parse Multiple IN1 Segment in HL7 using HAPI TERSER

问题描述

我正在接收HL7消息2.5.1版本.

I am receiving HL7 messages version 2.5.1.

MSH|..
PID|..
PV1|..
ORC|..
IN1|1|...
IN1|2|....

因此，在上面的示例中， IN1 在重复，但是当我尝试使用TERSER解析第二个IN1段时，它会抛出异常 不要创建结构IN1的重复#1-此结构是非重复的" .

So in the above example IN1 is repeating, however when i try to Parse the second IN1 segment with TERSER it throws an exception "Can't create repetition #1 of Structure IN1 - this Structure is non-repeating".

This is what i have tried so far

    string insurance = terser.Get("/.INSURANCE/.IN1(0)-1"); // Works fine
    string insurance = terser.Get("/.INSURANCE/.IN1(1)-1"); // Throws exception
string insurance = terser.Get("/.INSURANCE(0)/.IN1(0)-1"); // Works fine
    string insurance = terser.Get("/.INSURANCE(1)/.IN1(0)-1"); // Throws exception

推荐答案

您很近，但是您正在IN1上使用一个重复组，它不是一个重复片段.请记住，INSURANCE组重复的细分不是:

You are close but you are using a repeating group on IN1 which is not a repeating segment. Remember INSURANCE group is repeating the segments within are not:

Try:

/.INSURANCE(0)/.IN1-1"

/.INSURANCE(1)/.IN1-1"




"/.INSURANCE(1)/.IN1(0)-1" 

works because there's only one IN1 segment in the group (rep 0 defaults to the 1st segment in the group):

从 Terser api中阅读该部分在组上:

From the Terser api read up on the section on groups:

...

...

group_spec:[."] group_name_pattern

group_spec: ["."] group_name_pattern

在这里，一个.表示应搜索该组(使用 SegmentFinder)从消息中的当前位置开始.这 通配符""和?"代表任意数量的任意字符， 和一个任意字符.例如，"M "和 ?S?"匹配MSH.名称与给定名称匹配的第一组 group_name_pattern将被匹配.

Here, a . indicates that the group should be searched for (using a SegmentFinder) starting at the current location in the message. The wildcards "" and "?" represent any number of arbitrary characters, and a single arbitrary character, respectively. For example, "M" and "?S?" match MSH. The first group with a name that matches the given group_name_pattern will be matched.

segment_spec类似于group_spec.

The segment_spec is analogous to the group_spec.

另一个示例是SIU_S12消息中的以下子组件:

As another example, the following subcomponent in an SIU_S12 message:

msg.getSIU_S12_RGSAISNTEAIGNTEAILNTEAIPNTE(1).getSIU_S12_AIGNTE().getAIG().getResourceGroup(1).getIdentifier();

msg.getSIU_S12_RGSAISNTEAIGNTEAILNTEAIPNTE(1).getSIU_S12_AIGNTE().getAIG().getResourceGroup(1).getIdentifier();

...

: /SIU_S12_RGSAISNTEAIGNTEAILNTEAIPNTE(1)/SIU_S12_AIGNTE/AIG-5(1)-1 / AIG (1)/SIU_S12_AIGNTE/AIG-5(1)-1/ AIG (1)/.AIG-5(1)

is referenced by all of the following location_spec: /SIU_S12_RGSAISNTEAIGNTEAILNTEAIPNTE(1)/SIU_S12_AIGNTE/AIG-5(1)-1 /AIG(1)/SIU_S12_AIGNTE/AIG-5(1)-1 /AIG(1)/.AIG-5(1)

搜索功能仅迭代每个组的rep 0.因此，如果 在此示例中，期望第一组的rep 0代替rep 1， 以下语法也可以使用(因为只有一个AIG 段在SUI_S12中的位置):

The search function only iterates through rep 0 of each group. Thus if rep 0 of the first group in this example was desired instead of rep 1, the following syntax would also work (since there is only one AIG segment position in SUI_S12):

/.AIG-5(1)

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