删除序数超出范围的字符串中的所有字符 [英] Remove all characters from a string who's ordinals are out of range

问题描述

从python中的字符串中删除所有不在范围内的字符的好方法是什么?

What is a good way to remove all characters that are out of the range: ordinal(128) from a string in python?

我在python 2.7中使用hashlib.sha256.我遇到了例外情况:

I'm using hashlib.sha256 in python 2.7. I'm getting the exception:

UnicodeEncodeError:'ascii'编解码器无法对位置13处的字符u'\ u200e'进行编码:序数不在范围内(128)

UnicodeEncodeError: 'ascii' codec can't encode character u'\u200e' in position 13: ordinal not in range(128)

我认为这意味着某些时髦的字符进入了我要哈希的字符串中.

I assume this means that some funky character found its way into the string that I am trying to hash.

谢谢！

推荐答案

new_safe_str = some_string.encode('ascii','ignore') 

我认为会起作用

或者您可以进行列表理解

or you could do a list comprehension

"".join([ch for ch in orig_string if ord(ch)<= 128])

[edit]但是正如其他人所说的，通常最好弄清楚如何处理unicode ...除非出于某种原因您真的需要将其编码为ascii

[edit] however as others have said it may be better to figure out how to deal with unicode in general... unless you really need it encoded as ascii for some reason

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