春季启动:启动Webshere Application Server时会自动启动应用程序吗? [英] Spring boot: Start an application automatically when Webshere Application Server starts?
问题描述
假设我已经将SpringBoot应用程序部署为Websphere Application Server(WAS)的WAR.此WAR包含一个守护程序,因此它必须在WAS启动时立即启动(并且只能启动一次).
Assume I have a SpringBoot Application deployed as a WAR to Websphere Application Server (WAS). This WAR contains a daemon, so it must start straight away when WAS starts (and only once).
但是,我仍然需要通过执行http请求来激活SpringBoot Servlet.
However, I still need to activate the SpringBoot Servlet by doing a http request.
现在,我了解到servlet的概念是对http请求起作用,我仍然希望在appserver启动时自动启动它.这使我的守护程序可以从独立的jar/main移植到war/webapp.
我尝试了ServletContextListener
,但是contextInitalized
也仅在第一个http请求时被调用.
I tried a ServletContextListener
, but the contextInitalized
also get only called at the first http request.
我没有web.xml(Servlet 3).
I do not have a web.xml (servlet 3).
代码:
@SpringBootApplication
@WebListener
public class DemoApplication extends SpringBootServletInitializer implements ServletContextListener {
@Override
public void onStartup(ServletContext servletContext) throws ServletException {
System.err.println("ONSTARTUP");
super.onStartup(servletContext);
}
public static void main(String[] args) {
SpringApplication.run(DemoApplication.class, args);
}
@Override
protected SpringApplicationBuilder configure(SpringApplicationBuilder application) {
return application.sources(DemoApplication.class);
}
@Override
public void contextInitialized(ServletContextEvent sce) {
System.err.println("contextInitialized");
}
@Override
public void contextDestroyed(ServletContextEvent arg0) {
//
}
}
和:
@Component
public class DemoRunner implements ApplicationRunner {
@Override
public void run(ApplicationArguments arg0) throws Exception {
System.err.println("I AM RUNNING");
}
}
我刚开始时是这样的:
Launching defaultServer (WebSphere Application Server
16.0.0.2/wlp-1.0.13.cl160220160526-2258) on Java HotSpot(TM) 64-Bit Server VM, version 1.7.0_79-b15 (en_US)
[...]
[AUDIT ] CWWKT0016I: Web application available (default_host): http://localhost:9080/demo/
[AUDIT ] CWWKZ0001I: Application test started in 17,282 seconds.
要启动我的Spring Boot应用程序,我首先需要访问此链接(http:/localhost:9080/demo/).然后,它开始滚动,从启动方法开始,如您在日志中看到的那样.但是,如何在不执行http请求的情况下开始使用它?
[err] ONSTARTUP
. ____ _ __ _ _
/\\ / ___'_ __ _ _(_)_ __ __ _ \ \ \ \
( ( )\___ | '_ | '_| | '_ \/ _` | \ \ \ \
\\/ ___)| |_)| | | | | || (_| | ) ) ) )
' |____| .__|_| |_|_| |_\__, | / / / /
=========|_|==============|___/=/_/_/_/
:: Spring Boot :: (v1.4.0.RELEASE)
2016-09-02 10:45:52.670 INFO 23716 --- [dPool-thread-48] com.example.DemoApplication : Starting DemoApplication on [...]
2016-09-02 10:45:58.019 INFO 23716 --- [dPool-thread-48] o.s.c.support.DefaultLifecycleProcessor : Starting beans in phase 0
[...]
[err] I AM RUNNING
[...]
2016-09-02 10:45:58.093 INFO 23716 --- [dPool-thread-48] com.example.DemoApplication : Started DemoApplication in 6.372 seconds (JVM running for 31.549)
[...]
[err] contextInitialized
[err] contextInitialized
推荐答案
您可以通过自定义spring调度servlet来更改loadOnStartup
,这是示例问题,您可以使用代码
You can change the loadOnStartup
by customize the spring dispatch servlet, here is the sample question and you can use the code
@Bean
public static BeanFactoryPostProcessor beanFactoryPostProcessor() {
return new BeanFactoryPostProcessor() {
@Override
public void postProcessBeanFactory(
ConfigurableListableBeanFactory beanFactory) throws BeansException {
BeanDefinition bean = beanFactory.getBeanDefinition(
DispatcherServletAutoConfiguration.DEFAULT_DISPATCHER_SERVLET_REGISTRATION_BEAN_NAME);
bean.getPropertyValues().add("loadOnStartup", 1);
}
};
}
参考: 如何在Spring Boot启动时配置"dispatcherServlet"加载?
更新
似乎有一种更简单的方法,您可以在application.properites
Seems there is a more simple way, you can config it in application.properites
spring.mvc.servlet.load-on-startup=1
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