使用SPARQL查询的UNION和交集 [英] UNION and intersection using SPARQL queries

查看:628
本文介绍了使用SPARQL查询的UNION和交集的处理方法,对大家解决问题具有一定的参考价值,需要的朋友们下面随着小编来一起学习吧!

问题描述

我正在将用户定义的查询转换为SPARQL.例如,当用户说"abc"时,这意味着将具有给定类型的所有具有"abc"属性的节点提供给我.作为对此的扩展,如果用户说"abc或(pqr和lmn)",则需要找到给定类型的所有属性为"abc或(pqr和lmn)"的所有节点.以下是我提出的查询:

I am converting user-defined-queries into SPARQL. For example, when user says, "abc", it means give me all nodes of a given type which have some attribute named "abc". As an extension of this, if user says, "abc or (pqr and lmn)", I need to find all nodes of a given type for which some attribute is "abc or (pqr and lmn)". Following is the query I have come up with:

SELECT DISTINCT ?node, ?type                                                 
WHERE                                                                          
{
  {                                                                              
    ?node a ?type .                                                          
    FILTER ( ?type != <sometype>)
  }
{           
  {                                                                              
    ?node ?reln0 ?obj0 .                                                     
    FILTER ( regex(str(?obj0), 'abc', "i") )                           
  }                                                                              
  UNION                                                                          
  {                                                                              
    {                                                                              
      ?node ?reln1 ?obj1 .                                                     
      FILTER ( regex(str(?obj1), 'pqr', "i") )                                
    }
    {                                                                             
      ?node ?reln2 ?obj2 .                                                     
      FILTER ( regex(str(?obj2), 'lmn', "i") )                               
    }                                                                              
  }
}                                                                              
}                                                                              
ORDER BY ?node

但是它不会返回正确的结果.上述查询有问题吗?我不想使用以下内容,因为我需要动态生成条件,并且每个子句都必须分开.

But it doesn't return proper results. Is there something wrong with the above given query? I don't want to use the following because I need to generate the conditions dynamically and each clause needs to be separate.

FILTER (regex(str(?obj2), 'abc', "i") || regex(str(?obj2), 'pqr', "i") && regex(str(?obj2), 'lmn', "i"))

推荐答案

我使查询具体如下(为第一个过滤器输入确定的类型):

I made your query concrete as follows (putting in a definite type for the first filter):

PREFIX : <http://example.org/>

SELECT DISTINCT ?node ?type                                                 
WHERE                                                                          
{
    {                                                                              
        ?node a ?type .                                                          
        FILTER ( ?type != :Type1 )
    }
    {           
        {                                                                              
            ?node ?reln0 ?obj0 .                                                     
            FILTER ( regex(str(?obj0), 'abc', "i") )                           
        }                                                                              
        UNION                                                                          
        {                                                                              
            {                                                                              
                ?node ?reln1 ?obj1 .                                                     
                FILTER ( regex(str(?obj1), 'pqr', "i") )                                
            }
            {                                                                             
                ?node ?reln2 ?obj2 .                                                     
                FILTER ( regex(str(?obj2), 'lmn', "i") )                               
            }                                                                              
        }
    }                                                                              
}                                                                              
ORDER BY ?node

然后我生成了以下数据:

I then generated the following data:

@prefix : <http://example.org/> .

:n1 a :Type2 ;    # keep
    :r0 :NodeABC .

:n2 a :Type2 ;
    :r0 :NodeBCD .

:n3 a :Type2 ;     # keep
    :r1 :NodePQR ;
    :r2 :NodeLMN .

:n4 a :Type2 ;
    :r1 :NodeQRS ;
    :r2 :NodeLMN .

:n5 a :Type2 ;
    :r1 :NodePQR ;
    :r2 :NodeMNO .

:n6 a :Type2 ;
    :r1 :NodeQRS ;
    :r2 :NodeMNO .

仅应保留:n1:n3.我可以使用 Jena的命令行ARQ

Only :n1 and :n3 should be kept. I can run this with Jena's command line ARQ, or the Redland based roqet, and I get these rules in both cases.

使用ARQ:

$ arq --data data.n3 --query query.sparql
-----------------
| node | type   |
=================
| :n1  | :Type2 |
| :n3  | :Type2 |
-----------------

$ arq --version
Jena:       VERSION: 2.10.0
Jena:       BUILD_DATE: 2013-02-20T12:04:26+0000
ARQ:        VERSION: 2.10.0
ARQ:        BUILD_DATE: 2013-02-20T12:04:26+0000

使用roqet:

$ roqet query.sparql -D data.n3 -r table
roqet: Querying from file query.sparql
--------------------------------------------------------------
| node                       | type                          |
==============================================================
| uri<http://example.org/n1> | uri<http://example.org/Type2> |
| uri<http://example.org/n3> | uri<http://example.org/Type2> |
--------------------------------------------------------------

$ roqet -v
0.9.28

这篇关于使用SPARQL查询的UNION和交集的文章就介绍到这了,希望我们推荐的答案对大家有所帮助,也希望大家多多支持IT屋!

查看全文
登录 关闭
扫码关注1秒登录
发送“验证码”获取 | 15天全站免登陆