如何在APL中将数字分成数字 [英] How to split a number into its digits in APL

问题描述

在APL中，如何将整数或数字拆分为包含数字的向量?最简洁(最短)的方法是什么?

解决方案

您可以将Decode的倒数设为10:

10⊥⍣¯1⊢

由于Decode将根据需要输入尽可能多的数字并对其进行解码，因此它的逆运算将采用一个数字并将其编码为所需的任意数字，

，或者使用⎕IO←0，您可以尝试在数字矢量内查找带格式的数字的索引:

⎕D⍳⍕

解决方案

You can use the inverse of Decode with base 10:

10⊥⍣¯1⊢

since Decode would take in as many digits as needed and decode them, its inverse would take a number and encode it to as many digits as needed,

or, with ⎕IO←0, you can try to find the indexes of the formatted number inside the digits vector:

⎕D⍳⍕

Demo for both solutions.

This is better than the uglier use of Encode with custom length derived by shaping an array of 10 to the length of the log₁₀ of the input:

{⍵⊤⍨10⍴⍨⌈10⍟1+⍵}

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