javascript:在.replace中进行异步/等待 [英] javascript : Async/await in .replace
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问题描述
我正在通过以下方式使用async/await函数
I am using the async/await function the following way
async function(){
let output = await string.replace(regex, async (match)=>{
let data = await someFunction(match)
console.log(data); //gives correct data
return data
})
return output;
}
但是返回的数据是一个Promise对象.只是对应该在带有回调的此类函数中实现它的方式感到困惑.
But the returned data is an promise object. Just confused about the way it should be implemented in such functions with callback.
推荐答案
一个易于使用和理解的异步替换功能:
An easy function to use and understand for some async replace :
async function replaceAsync(str, regex, asyncFn) {
const promises = [];
str.replace(regex, (match, ...args) => {
const promise = asyncFn(match, ...args);
promises.push(promise);
});
const data = await Promise.all(promises);
return str.replace(regex, () => data.shift());
}
它执行两次替换功能,因此请注意是否要进行繁重的处理.不过,对于大多数用法来说,它非常方便.
It does the replace function twice so watch out if you do something heavy to process. For most usages though, it's pretty handy.
像这样使用它:
replaceAsync(myString, /someregex/g, myAsyncFn)
.then(replacedString => console.log(replacedString))
或者这个:
const replacedString = await replaceAsync(myString, /someregex/g, myAsyncFn);
别忘了您的myAsyncFn
必须返回承诺.
Don't forget that your myAsyncFn
has to return a promise.
asyncFunction的示例:
An example of asyncFunction :
async function myAsyncFn(match) {
// match is an url for example.
const fetchedJson = await fetch(match).then(r => r.json());
return fetchedJson['date'];
}
function myAsyncFn(match) {
// match is a file
return new Promise((resolve, reject) => {
fs.readFile(match, (err, data) => {
if (err) return reject(err);
resolve(data.toString())
});
});
}
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