将方法命名为变量调用方法Ruby [英] naming methods as variables calling methods Ruby

问题描述

我非常初学者.

我想我了解attr_accessor的工作原理(如下).而设置者"是name=(name)方法.而且我知道该方法等效于赋值:name = "john".因为"="是一种接受参数并将该参数分配给任何对象调用它的方法. (尽管我不明白在将名称"分配给对象时如何将其视为对象)

i think i understand how the attr_accessor works (below). and the "setter" is the name=(name) method. and i know that that method is equivalent to the assignment: name = "john". because "=" is a method that accepts an argument and assigns that argument to whatever object calls it. (though i don't understand how "name" could be considered an object as it is being assigned to an object)

所以我的问题是:如何分配一个调用方法的变量作为方法名称?感觉好像我缺少什么..

so my question is: how can you assign a variable calling a method as a method name? It feels like I'm missing something..

class Person
  def name
    @name
  end

  def name=(name)
    @name = name
  end
end

推荐答案

所以我的问题是:如何分配一个将方法调用为 方法名称?感觉好像我缺少什么..

so my question is: how can you assign a variable calling a method as a method name? It feels like I'm missing something..

你不知道.在这段代码中

You don't. In this code

def name=(name)
  @name = name
end

name= 不是不是调用方法=的变量name.方法的名称是name=.

name= isn't a variable name calling a method =. The name of the method is name=.

在上面的代码片段中，def与终止的end配对构成方法定义.

In the above code snippet the def paired with a terminating end constitutes a method definition.

def method_name(param1, param2)
  # method body
end

与def在同一行上，只能有方法名称，可选的括号和参数列表.根据定义，在该行中具有变量调用方法"将是非法的.因此，在您的代码中，name=是方法名称.

On the same line as def there can only be the method name, optional parentheses, and the param list. By definition having a "variable calling a method" in that line would be illegal. So in your code name= is the method name.

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