python pymysql设置自动提交false失败 [英] python pymysql set autocommit false fails

问题描述

我的脚本从文件中读取MYSQL UPDATE查询，然后应通过使用autocommit = 0立即执行它们.但是，如果删除conn.commit()，它仍会逐个运行，尽管我尚未提交.错误在哪里?

my script reads MYSQL UPDATE queries from a file and then should execute them at once by using autocommit = 0. However, if I remove conn.commit() it still runs one by one, although I have not commited. Where is the error?

import pymysql
conn = pymysql.connect(host='x', unix_socket='/tmp/mysql.sock',user='x', passwd='x', db='x')
fileHandle = open ( 'mysqlout.txt' )
fileList = fileHandle.readlines()
fileHandle.close()
i = 1
weiter = input("Execute MYSQL file? ")
if (weiter == 'y'):
    cur = conn.cursor()
    cur.execute('SET autocommit = 0')
    conn.commit()
    for fileLine in fileList: #-----each line is an UPDATE...query
        cur.execute(fileLine)
        i = i + 1
        print(i," ---",round(i / len(fileList),3))
#conn.commit()
conn.close()

推荐答案

MySQL中的MyISAM存储引擎不支持事务.只有InnoDB支持ACID事务.

Transactions are not supported with MyISAM storage engine in MySQL. Only InnoDB suports ACID transactions.

引用事务和原子操作MySQL文档:

就事务而言，MyISAM表始终有效地在 自动提交= 1模式.

In transactional terms, MyISAM tables effectively always operate in autocommit = 1 mode.

您应检查存储引擎是否适合您表格:

mysql> SELECT table_name,engine FROM INFORMATION_SCHEMA.TABLES 
       WHERE table_schema=DATABASE();
+--------------+--------+
| table_name   | engine |
+--------------+--------+
| stats        | MyISAM |
+--------------+--------+
1 row in set (0.00 sec)

将表移动到 MySQL存储引擎支持交易.

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