改变输出 [英] changing the output

问题描述

可能重复:
略微更改输出

Possible Duplicate:
Changing the output a bit

问题是:

voting_borda:

(str列表)->(str，int列表)的元组

(list of list of str) -> tuple of (str, list of int)

该参数是由4个元素组成的列表的列表，代表单次骑行的等级投票.

The parameter is a list of 4-element lists that represent rank ballots for a single riding.

Borda计数是通过根据排名分配分数来确定的.一方的第一选择排名获得3分，第二选择排名获得2分，第三选择排名获得1分. (如果获得第四名，则不会获得任何积分.)例如，上面显示的等级投票对自由党议员贡献3分，对绿色议员贡献2分，对CPC贡献1分.得分最高的一方将赢得席位.

The Borda Count is determined by assigning points according to ranking. A party gets 3 points for each first-choice ranking, 2 points for each second-choice ranking and 1 point for each third-choice ranking. (No points are awarded for being ranked fourth.) For example, the rank ballot shown above would contribute 3 points to the Liberal count, 2 points to the Green count and 1 point to the CPC count. The party that receives the most points wins the seat.

返回一个元组，其中第一个元素是根据Borda Count的获胜方的名称，第二个元素是一个包含四个元素的四元素列表，其中包含每个政党的积分总数.列表元素的顺序与PARTY_INDICES中各方的顺序相对应.

Return a tuple where the first element is the name of the winning party according to Borda Count and the second element is a four-element list that contains the total number of points for each party. The order of the list elements corresponds to the order of the parties in PARTY_INDICES.

这是我的代码:

def voting_borda(*args):
results = {}
for sublist in args:
    for i in range(0, 3):
        if sublist[i] in results:
            results[sublist[i]] += 3-i
        else:
            results[sublist[i]] = 3-i

winner = max(results, key=results.get)
return winner, results

但是，如果我尝试

voting_borda(['GREEN','NDP', 'LIBERAL', 'CPC'],['GREEN','CPC','LIBERAL','NDP'],['LIBERAL','NDP', 'CPC', 'GREEN'])

我明白了

('GREEN', {'NDP': 4, 'CPC': 3, 'GREEN': 6, 'LIBERAL': 5})

但是，我希望第一个参数成为获胜者(那部分很好)，第二个参数只是值，并且也应按照PARTY_INDICES的顺序排列，即 PARTY_INDICES = [NDP_INDEX, GREEN_INDEX, LIBERAL_INDEX, CPC_INDEX].

But, I want the first parameter to be the winner(that part is fine), and the second parameter to be just the values and also to be in the order of PARTY_INDICES which is PARTY_INDICES = [NDP_INDEX, GREEN_INDEX, LIBERAL_INDEX, CPC_INDEX].

我可以做得更好的任何解决方案或方法吗?

any solutions or ways that i could make this better?

推荐答案

PARTY_INDICES = ['NDP_INDEX', 'GREEN_INDEX', 'LIBERAL_INDEX', 'CPC_INDEX']
party_dic = {}

for i, item in enumerate(PARTY_INDICES):
    party_dic[item.split('_')[0]] = i

print party_dic

def voting_borda(*args):
    results = {}
    for sublist in args:
        for i in range(0, 3):
            if sublist[i] in results:
                results[sublist[i]] += 3-i
            else:
                results[sublist[i]] = 3-i

    winner = max(results, key=results.get)
    results = [v for k, v in sorted(results.items(), key = lambda x: party_dic[x[0]])]
    return winner, results


print voting_borda(['GREEN','NDP', 'LIBERAL', 'CPC'],['GREEN','CPC','LIBERAL','NDP'],['LIBERAL','NDP', 'CPC', 'GREEN'])


{'NDP': 0, 'CPC': 3, 'GREEN': 1, 'LIBERAL': 2}
('GREEN', [4, 6, 5, 3])

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